Answer:
0.00370 g
Explanation:
From the given information:
To determine the amount of acid remaining using the formula:
where;
v_1 = volume of organic solvent = 20-mL
n = numbers of extractions = 4
v_2 = actual volume of water = 100-mL
k_d = distribution coefficient = 10
∴
Thus, the final amount of acid left in the water = 0.012345 * 0.30
= 0.00370 g
<u>Explanation:</u>
pH is the negative logarithm of hydronium ion concentration present in a solution.
To calculate the pH of the solution, we use equation:
......(1)
To calculate the pOH of the solution, we use the equation:
pH + pOH = 14 ........(2)
We are given:
pH = 5.54
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 5.54 + pOH
pOH = 8.46
The solution is acidic in nature.
We are given:
pOH = 9.7
Putting values in equation 2, we get:
14 = 9.7 + pH
pH = 4.3
Now, putting values in equation 1, we get:
The solution is acidic in nature.
We are given:
pH = 7.0
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 7.0 + pOH
pOH = 7.0
The solution is neither acidic nor basic in nature.
We are given:
pH = 12.9
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 12.9 + pOH
pOH = 1.1
The solution is basic in nature.
We are given:
pOH = 1.2
Putting values in equation 2, we get:
14 = 1.2 + pH
pH = 12.8
Now, putting values in equation 1, we get:
The solution is basic in nature.
We are given:
Putting values in equation 1, we get:
Now, putting values in equation 2, we get:
14 = 5 + pOH
pOH = 9
The solution is acidic in nature.