Answer:
13.33m/s
Explanation:
Given data
m1= 2000kg
u1= 20m/s
m2= 1500kg
u2= 0m/s
v1= 10m/s
Required
The speed of the sticks
We know that from the expression for the conservation of momentum
m1u1+m2u2= m1v1+m2v2
2000*20+1500*0=2000*10+1500*v2
40000=20000+1500v2
collect like terms
40000-20000= 1500v2
20000= 1500v2
v2= 20000/1500
v2= 13.33 m/s
Hence the velocity of the sticks is 13.33m/s
Answer:
Watershed should be your answer!
Answer:
1066.67 m
Explanation:
Given:
v₀ = 96 km/h = 26.67 m/s
v = 48 km/h = 13.33 m/s
Δx = 800 m
Find: a
v² = v₀² + 2aΔx
(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)
a = -0.333 m/s²
Given:
v₀ = 26.67 m/s
v = 0 m/s
a = -0.333 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx
Δx = 1066.67 m
Round as needed.
Answer:
Ah good question um no u dont have to be near it its a vr thing ur gonna have it on u the whole time. You can only be a few feet away from ur tv if u chose to do it on there or u can do it on ur phone but its also the same distance.
Explanation:
Answer:
d = 49.5 m
hence we can say it is conceivable that he can distinguish sports stadiums on earth's surface but in Private houses? Cars? it can not becayuse they are are very small
Explanation:
Given data
altitude = 150 km
diameter = 2.0 mm
wavelength = 550 nm
to find out
is it conceivable that he can distinguish sports stadiums
solution
we will apply here formula that is
∅ = 1.2 λ / D
put here λ = 550 ×
m and D = 2 ×
m
∅ = (1.2 ) 550 ×
/ 2 ×
∅ = 3.30 ×
rad
so
d = 150 ×
× 3.30 ×
d = 49.5 m
hence we can say it is conceivable that he can distinguish sports stadiums on earth's surface but in Private houses? Cars? it can not becayuse they are are very small