A 2000-kg car moving with a speed of 20 m/s collides with and sticks to a 1500-kg car at rest at a stop sign. Show that because
1 answer:
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Answer:
10259.6 m
Explanation:
We are given that
Radius of small wheel,r=0.17 m
Radius of large wheel,r'=0.92 m
Initial velocity,u=0
Time,t=2.7 minutes=162 s
1 min=60 s
Velocity,v=10m/s
Time,t'=13.7 minutes=822 s
Time,t''=4.1 minutes=246 s
Substitute the values
Substitute the values
Total distance traveled by rider=s+s'+s''=809.6+8220+1230=10259.6 m
The P value for the given data set is 25127. For finding P value, we have to must find the Z value.
<h3>How to get the z scores?</h3>If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.
The Z value is calculated as;
Z = (X - μ) / σ
Z = (4.007 - 3.6) / 0.607
Z = 0.67051
The P value for the given data set is 25127.
Learn more about z-score here:
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The maximum speed is 10.4 m/s
Explanation:
For a body in uniform circular motion, the centripetal acceleration is given by:
where
v is the linear speed
r is the radius of the circular path
In this problem, we have the following data:
- The maximum centripetal acceleration must be
where is the acceleration of gravity. Substituting,
- The radius of the turn is
r = 10 m
Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:
Learn more about centripetal acceleration:
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