Answer:
v = 5.15 m/s
Explanation:
At constant velocity, the cable tension will equal the car weight of 984(9.81) = 9,653 N
As the cable tension is less than this value, the car must be accelerating downward.
7730 = 984(9.81 - a)
a = 1.95 m/s²
kinematic equations s = ut + ½at² and v = u + at
-5.00 = u(4.00) + ½(-1.95)4.00²
u = 2.65 m/s the car's initial velocity was upward at 2.65 m/s
v = 2.65 + (-1.95)(4.00)
v = -5.15 m/s
Answer:
none of the above
Explanation:
im pretty positive this is the answer tell me if i am wrong please
I would think something like fire or a torch because that seems like it means heat or maybe a campfire picture
Intensity, E follows inverse square law.
E α 1/r²
r is the distance.
So if the distance r is increased by 3, the intensity would be reduced by 3²
3² = 9
So the answer is nines times as low. C.
Multiplying the ideal gas law constant
