Answer:
3.67 m/s
Explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision.
mu+m'u' = mv+m'v'............................... Equation 1
Where m = mass of the bullet, m' = mass of the watermelon, u = initial velocity of the bullet, u' = initial velocity of the watermelon, v = final velocity of the bullet, v' = final velocity of the watermelon.
make v' the subject of the equation,
v' = (mu+m'u'-mv)/m'....................... Equation 2
Given: m = 25 g = 0.025 kg, u = 220 m/s, m' = 2.25 kg, u' = 0 m/s ( at rest), v = 110 m/s.
Substitute into equation 2
v' =[ (0.025×220) +(2.25×0)+(0.025×110)]/2.25
v' = 3.67 m/s.
Hence the velocity of the watermelon = 3.67 m/s
