Answer:
695800 N/m^2 or Pa
Explanation:
Height of the water from the ground H = 71 m
Acceleration due to gravity g =9.8 m/s^2
density of water ρ= 1000 kg/m^3
The minimum output gauge pressure to make water reach height H
P= ρgH
= 1000×9.8×71= 695800 N/m^2 or Pa
Answer:
3.7 N/kg
Explanation:
The gravitational strength refers to the amount of gravity acting per unit mass. Hence in this case,
Gravitational Strength = Weight / Mass
= 370 / 100
= <u>3</u><u>.</u><u>7</u><u>N</u><u>/</u><u>k</u><u>g</u>
Answer:
physical measurement comprises the measurement of objects, things, etc. and is concerned with the measurement of height, weight, length, size, volume etc.
Answer:
Its initial position was 471 m.
Explanation:
We have,
Final position of the object is 327 m
Displacement of the object is -144 m
It is required to find its initial position. The difference of final and initial position is equal to the displacement of the object. So,
So, its initial position was 471 m.
