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Nina [5.8K]
3 years ago
6

Which pair of scientists should Elizabeth write instead of X

Physics
2 answers:
ASHA 777 [7]3 years ago
5 0

Answer:

O Hooke and Leeuwenhoek

Explanation:

O Hooke and Leeuwenhoek discovered the existence of micro organisms between 1665 and 1683

m_a_m_a [10]3 years ago
5 0

Answer:

O Hooke and Leeuwenhoek

Explanation:

The scientists, O Hooke and Leeuwenhoek were prominent scientists.  In fact, they are credited with being the pioneers of science especially the field of microorganisms. To be more specific, the two great scientists discovered what are known as protozoa. This was done specifically by Van Leeuwenhoek who discovered the single celled protozoa ,which were termed animalcules. In addition, the most prominent feature of the research and discovery was Leeuwenhoek's use of a self-designed microscope.  

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Describe in your own words materialism and dualism as two contrasting positions on the mind-body problem. List a couple of criti
Nat2105 [25]

Materialism and dualism are two different ideologies about mind and physical body.

<h3>What is Materialism?</h3>

Materialism in philosophy of mind refers to the theory or idea that all facts are dependent upon physical processes, or even reducible to them.

<h3>What is dualism?</h3>

In the philosophy of mind, dualism is the theory that the mental and the physical are, in some sense, different kinds of thing from each other.

Learn more about theory here: brainly.com/question/11555274

3 0
3 years ago
Consider the differential equation
Zielflug [23.3K]
Yp(t) = A1 t^2 + A0 t + B0 t e(4t)

=> y ' = 2A1t + A0 + B0 [e^(4t) +4 te^(4t) ]

     y ' = 2A1t + A0 + B0e^(4t) + 4B0 te^(4t)

=> y '' = 2A1 + 4B0e(4t) + 4B0 [ e^(4t) + 4te^(4t)

     y '' = 2A1 + 4B0e^(4t) + 4B0e^(4t) + 16B0te^(4t)

Now substitute the values of y ' and y '' in the differential equation:

 
<span>y′′+αy′+βy=t+e^(4t)


</span> 2A1 + 4B0e^(4t) + 4B0e^(4t) + 16B0te^(4t) + α{2A1t + A0 + B0e^(4t) + 4B0 te^(4t) } + β{A1 t^2 + A0 t + B0 t e(4t)} = t + e^(4t)

Next, we equate coefficients

1) Constant terms of the left side = constant terms of the right side:

2A1+ 2αA0 = 0 ..... eq (1)

2) Coefficients of e^(4t) on both sides

8B0 + αB0 = 1 => B0 (8 + α) = 1 .... eq (2)

3) Coefficients on t

2αA1 + βA0 = 1 .... eq (3)


4) Coefficients on t^2

βA1 = 0 ....eq (4)

given that A1 ≠ 0 => β =0

5) terms on te^(4t)

16B0 + 4αB0 + βB0 = 0 => B0 (16 + 4α + β) = 0 ... eq (5)

Given that B0 ≠ 0 => 16 + 4α + β = 0

Use the value of β = 0 found previously

16 + 4α = 0 => α = - 16 / 4 = - 4.

Answer: α = - 4 and β = 0
  




3 0
4 years ago
What characteristic of an element determines how its atoms can bond with other<br>atoms?​
wlad13 [49]

Answer:

The number of electron in the outermost shell of a particular atom determine how the reactivity of  atoms to form chemical bonds with other atoms

Explanation:

This is because the number of atoms in the outer shell will determine if the atom has to gain or loose electrons for it to bond with other atoms

Hope this helps, and if it does mark as branliest answer thx

8 0
3 years ago
Read 2 more answers
Which of the following is a compound machine
Ivahew [28]

The answer is c.

Hope this helps!!!!!!!!!!

8 0
4 years ago
Read 2 more answers
An electron has a velocity of 3.2 x 10^6 m/s. What is its’ momentum? (b) What is its’ wavelength? (c) What other objects/materia
Romashka [77]

Answer:

P = 2.91*10^{-24} kg m/s

\lambda = 2.73 *10^{-10} m

size of atom hat lie in range of 1 to 5 Angstrom

\Delta x = 0.2272 Angstrom

Explanation:

A) MOMENTUM

p = mv

where m is mass of electron

so momentum p can be calculated as

p = 9.11*10^{-31} *3.2*10^{6}

P = 2.91*10^{-24} kg m/s

b) wavelength

\lambda = \frac{h}{mv}

where h is plank constant

so\lambda = \frac{6.626*10^{-34}}{2.91*10^{-24}}

\lambda = 2.73 *10^{-10} m

c) size of atom hat lie in range of 1 to 5 Angstrom

d) from the information given in the question we have

\frac{\Delta v}{v} = 0.1

\Delta v = 0.1 v

we know that

\Delta p *\Delta x = \frac{h}{4\pi}

m \Delta v \Delta x =\frac{h}{4\pi}

\Delta x = \frac{h}{m \Delta v}

\Delta x  = \frac{2.272}{0.1}                      [\Delta v = 0.1 v]

\Delta x = 0.2272 Angstrom

7 0
4 years ago
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