Answer:
Explanation:
In the whole process , electric potential energy is converted into kinetic energy .
Kinetic energy = 3.83 MeV
= 3.83 x 1.6 x 10⁻¹⁶ J
= 6.128 x 10⁻¹⁶ J .
Let the closest distance of approach be r .
Electric potential energy = k Q q / r , Q is charge on nucleus , q is charge on alpha particle , r is closest distance .
Electric potential energy = 9 x 10⁹ x 79 x 1.6 x 10⁻¹⁹ x 2 x 1.6 x 10⁻¹⁹ / r
= 3640.32 x 10⁻²⁹ / r
So,
6.128 x 10⁻¹⁶= 3640.32 x 10⁻²⁹ / r
r = 3640.32 x 10⁻²⁹ / 6.128 x 10⁻¹⁶
= 594.05 x 10⁻¹³
= 59.405 x 10⁻¹²
= 59.405 pm .
The final speed of the car is 2) 150 m/s
Explanation:
Since the motion of the car is a uniformly accelerated motion, we can solve the problem by using the following suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the car in this problem, we have
u = 10 m/s

s = 7,467 m
Solving for v, we find the final velocity (and speed) of the car:

Learn more about accelerated motion:
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Answer:
Because they would naturally dye the test strips in the colors violet and red, regardless of their pH values
(would really appreciate the brainliest)
Answer:

Explanation:
From the question we are told that
Weight of fireman 
Pole distance 
Final speed is 
Generally the equation for velocity is mathematically represented as

Therefore Acceleration a
Generally the equation for Frictional force
is mathematically given as



Therefore
