The specific heat of aluminum is actually simply a
diversion. Because we can directly compute for the specific heat of copper
using the formula:
ΔH = m C ΔT
where ΔH is change in enthalpy or heat lost, m is mass, C
is specific heat and ΔT is change in temp
4,600 J = 150 g * C * (100 °C - 20°C)
C = 0.38 J/g°C
Answer: (a) 99.5℅ submerged
(B) 96.9℅ submerged
Explanation:
For 995 kilograms per cubic meter, It'll be the 995Kg/m3 density given, divided by the density of fresh water, which is one times ten to the three kilograms per cubic meter, and this works out to 99.5 percent submerged.
If the same person with the same density was floating in salt water, salt water has a slightly higher density of 1027 kilograms per cubic meter, this works out to 96.9 percent submerged.
Answer:using Newton third law
Let initial velocity of block be u1=3m/s
Mass of moving block m1 =1kg
Final velocity of block =V
Mass of stationary block m2= 4kg
Since they stick together, their final velocity will be the same.
m1u1 + m2u2=(m1+m2)v
(1*3)+(0*4)=(1+4)v
3=5v
Divide both sides by 5
V=0.6
Final velocity is 0.6m/s
Explanation:
Answer:350.92 KJ/kg
Explanation:
Given the process is reversible adiabatic i.e it is isentropic
From steam table
For isentropic process 
at
Therefore Work output of the turbine per unit mass of steam is =
=3317.03-2966.11
=350.92 KJ/kg
