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givi [52]
3 years ago
14

When driving a Toyota avensis car along a straight road for 16.5km at

Physics
1 answer:
Vitek1552 [10]3 years ago
7 0

The average velocity of the whole journey will be total distance covered divided by the total time. It will be approximately equal to 8 m/s. The right answer is option B

<h2>VELOCITY</h2>

Velocity is the distance travelled in a specific direction. While the average velocity of the whole journey will be total distance covered divided by the total time

When driving a Toyota avensis car along a straight road for 16.5km at

50km/h,

The velocity = 50 km/h

Distance = 16.5 km

Use the speed formula to calculate time.

Speed = distance / time

Time = distance / speed

Time = 16.5 / 50

Time = 0.33 s

If over the next 20min, you walked another 2.5km further along the road for a petrol station, Then,

average velocity = Total distance covered divided by total time taken.

Where

The time t = 20/60 = 0.333 h

Total time = 0.33 + 0.3333

Total time = 0.6633333

Total distance = 16.5 + 2.5

Total distance = 19 km

Average velocity = 19 / 0.66333

Average Velocity = 28.64 km/h

Now convert Km/h to m/s

(28.6432 x 1000) / 3600

286432 / 3600

7.956m/s

Therefore, the average velocity of the whole journey from beginning of the drive to the arrival at the filling station will be approximately 8 m/s

Learn more about velocity here: brainly.com/question/6504879

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Answer:

factors that affect the force of gravity between objects include their distance apart and their mass.

Explanation:

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A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. the wire ful
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Answer:

The force is "19 µN".

Explanation:

The lane's j-component is meaningless, as the current is flowing in the -j line.  

Therefore the power is now in the direction of + z (out of the page if x and y are in the page plane) and has the magnitude.

\ formula: \\\\\ Forec (F) = mA \\\\ \ F \ = 2.0mA \times \int {0.3} \ y \ dy  \rightarrow  \ from\ 0 \ to \ 0.25 \\\\\ F \ = \ 2.0mA \times 0.15 * 0.25^{2} m\cdot T \\\\ F = 19 \µN

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3 years ago
A space station has a mass M and orbits Earth in a circular orbit at a height above Earth’s surface. An astronaut in the space s
Svetllana [295]

Answer:

The correct option is;

D) The force exerted on the astronaut by Earth is equal to the force exerted on Earth by the astronaut

Explanation:

According to Newton's third law of motion, in nature, for every action, there is an equal and opposite reaction, such that if a first object exerts a certain amount of force on a second object, the second object will exert a force of equal magnitude and opposite direction to that exerted by the first object

Therefore, the gravitational force exerted by Earth on the astronaut, is equal to the force exerted by the astronaut on Earth.

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3 years ago
In a chemical reaction, the bonds in the molecules
notsponge [240]

Answer:

B. change

Explanation:

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3 years ago
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Two positive charges of 20 micro coulomb and 100 micro coulomb and the distance between them is 150cm.What will be the electrica
Roman55 [17]

Answer:

0.8 N

Explanation:

From coulomb's law,

Formula:

F = kqq'/r²........................ Equation 1

Where F = Force of repulsion, k = coulomb's constant, q = first positive charge, q' = second positive charge, r = distance between the charge.

Given: q = 20 μC = 20×10⁻⁶ C, q' = 100 μC = 100×10⁻⁶ C, r = 150 cm = 1.5 m.

Constant:  k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (20×10⁻⁶ )( 100×10⁻⁶)(9×10⁹)/1.5²

F = 1800×10⁻³/2.25

F = 1.8/2.25

F = 0.8 N

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3 years ago
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