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Anna007 [38]
3 years ago
6

Explain the process behind the scientific method and how it has the potential to lead to a "feedback loop".

Physics
2 answers:
Nina [5.8K]3 years ago
5 0
Scientific method is a process wherein there is a common end result at the end of each milestone of the research. This is to improve the problem which was intended to be realized at the beginning of conducting or applying scientific method. The feedback loop is the part of the model which allows for continuous improvement of the method, for each result there may be atleast known and observed result analysis which is feedback to a step or the whole process for the betterment of the cycle.
DENIUS [597]3 years ago
3 0

Answer:

The scientific method uses 5 steps in the process of analyzing evidence. First, they observe the phenomenon, meaning they would visit the crime scene, the lab or the autopsy. Second, they create a hypothesis as to what happened, third they make predictions about what they will observe while testing the hypothesis and fifth is extermination where they test their predictions. The feedback loop is a continuous loop whereby no matter how many tests you take there is always another test you can take.

Explanation:

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(a) If the maximum acceleration that is tolerable for passengers in a subway train is 1.34 m/s² and subway stations are located
andreev551 [17]

Answer:

The correct answer is 32.9 m/s

Explanation:

To solve this, we list out the known and the unknown variables as follows

Maximum allowable acceleration = 1.34 m/s²

Distance between sttions = 806 m

Therefore from the equation of motion

v = ut + 0.5·×at²

Where v = final velocity

u = initial velocity

S = distance covered

t  = time

a = acceleration

Also v² = u² + 2·a·S

where u is the initial velocity, which we can take as u = 0, then

v² = 2·1.34·S = 2.68S m²/s²  then

Also the train has to decelerate from maximum speed to stop at the next tran station wherev = 0, thus v² = u² -2·1.34·Z,  so u² = 2.68Z

since u² = 2.68S from the previous calculation, then for v = 0

2.68S = 2.68Z thus S = Z which and to reach the next subway station S + Z must be = 806 m, then S = 806 m ÷ 2 = 403 m

and v² = 2.68S m²/s² = 1080.04 m²/s²

v = 32.9 m/s

The maximum speed a subway train can attain between stations is 32.9 m/s

3 0
3 years ago
If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 2.52 m from the base of the
tamaranim1 [39]

Answer:

The height of the water slide is 0.878 m

Explanation:

Given that,

Distance = 2.52 m

Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value in the equation

1.80=0+\dfrac{1}{2}\times9.8\times t^2

t^2=\dfrac{1.80\times2}{9.8}

t=\sqrt{\dfrac{1.80\times2}{9.8}}

t=0.606\ sec

We need to calculate the velocity

Using formula of velocity

v = \dfrac{d}{t}

Put the value into the formula

v=\dfrac{2.52}{0.606}

v=4.15\ m/s

We need to calculate height

Using conservation of energy

\dfrac{1}{2}mv^2=mgh

h=\dfrac{v^2}{2g}

Put the value into the formula

h=\dfrac{4.15^2}{2\times9.8}

h=0.878\ m

Hence, The height of the water slide is 0.878 m.

4 0
3 years ago
What is the force of gravity between two 50.0kg masses that are separated by 0.300m?3.71x10-8N5.59x10-7N2.78x104N1.85x10-6N
Varvara68 [4.7K]

We will have the following:

\begin{gathered} F=G\frac{m_1m_2}{r^2}\Rightarrow F=\frac{(6.67\ast10^{-11}m^3\ast kg^{-1}\ast s^{-2})(50kg)(50kg)}{(0.3m)^2} \\  \\ \Rightarrow F=1.852777778...\ast10^{-6}N\Rightarrow F\approx1.85\ast10^{-6}N \end{gathered}

So, the force is approximately 1.85*10^-6 N.

7 0
1 year ago
a toy propeller fan with a moment of inertia of .034 kg x m^2 has a net torque of .11Nxm applied to it. what angular acceleratio
Harman [31]

Answer:

The  angular acceleration is  \alpha  = 3.235 \ rad/s ^2

Explanation:

From the question we are told that

    The moment of inertia is  I  =  0.034\ kg \cdot m^2

     The  net torque is  \tau  =  0.11\ N \cdot m

Generally the net torque is mathematically represented as

           \tau =  I  *  \alpha

Where \alpha is the angular acceleration so  

        \alpha  =  \frac{\tau }{I}

substituting values

         \alpha  =  \frac{0.1 1}{ 0.034}

        \alpha  = 3.235 \ rad/s ^2

6 0
3 years ago
A uniform disk, a uniform hoop, and a uniform solid sphere are released at the same time at the top of an inclined ramp. They al
pav-90 [236]

Answer:

sphere, disk, hoop

Explanation:

See attached file

8 0
3 years ago
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