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Pavlova-9 [17]
2 years ago
13

The speed of a bus is reduced uniformly from 20 m/s to 10 m/s while traveling 60 m. (a)

Physics
1 answer:
kherson [118]2 years ago
7 0

The bus will travel a further 20 m before coming to rest.

<h3>What is acceleration?</h3>

The term acceleration has to do with a change in velocity with time. Now we have;

u = 20 m/s

v = 10 m/s

s =  60 m

Now;

v^2 = u^2 -2as

v^2 -  u^2 = -2as

(10)^2 - (20)^2 = - 2 * a * 60

a = (10)^2 - (20)^2/ - 2 * 60

a = 100 - 400/ - 2 * 60

a = 2.5 m/s^2

At that time;

v = 0 m/s

u = 20 m/s

a = 2.5 m/s^2

s = ?

Hence;

u^2 = 2as

s = u^2/2a

s = (20)^2/ 2 *  2.5

s = 400/5

s = 80 m

Hence, the bus will travel a further 20 m before coming to rest.

Learn more about acceleration:brainly.com/question/12550364

#SPJ1

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Answer:

26.466cm³/min

Explanation:

Given:

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pressure P and volume V are related by the equation

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we need to find dV/dt, so we will differentiate the above equation

V^{1.4} \frac{dP}{dt} + P\frac{d[V^{1.4} ]}{dt}  = \frac{d[C]}{dt}

\frac{dP}{dt} V^{1.4} + P(1.4)V^{0.4} \frac{dV}{dt} =0

lets solve for dV/dt, we will have

\frac{dV}{dt} =\frac{-\frac{dP}{dt} V^{1.4} }{P(1.4)V^{0.4} } \\\frac{dV}{dt} =- \frac{-\frac{dP}{dt} V}{P(1.4)}

\frac{dV}{dt} = -\frac{(-11 ) 320}{95(1.4)}  (plugged in all the values at the instant)

\frac{dV}{dt} = 26.466

Therefore, the volume increasing at the rate of 26.466cm³/min at this instant

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3 years ago
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A pendulum bob is made from a sphere filled with water. What would happen to the frequency of vibration of this pendulum if the
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Explanation:

7 0
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Beth made the chart shown.
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X: Use DC

Y: Use AC

Explanation:

The objects: Wall clock, T V remote control, Portable music player, are normally powered by batteries, which run DC current.

On the other hand, the objects: Refrigerator, Table lamp, Hair dryer, demand much larger power, and are normally run from the AC plug on the wall.

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Calculate the wavelength of an electron mass 9.1*10^-31kg moving with a velocity of 2.0*10^6m/s (h=6.63*10^-34Js) (Hint: De Brog
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Answer:

Wavelength, \lambda=3.64\times 10^{-10}\ m

Explanation:

We have,

Velocity an electron is 2\times 10^6\ m/s

Mass of an electron is 9.1\times 10^{-31}\ kg

It is required to find the wavelength of electron. The De-Broglie wavelength of an electron is given by :

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\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^6}\\\\\lambda=3.64\times 10^{-10}\ m

So, the wavelength of an electron is 3.64\times 10^{-10}\ m.

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