Answer:
Explanation:
Given that on the tree the gravitational energy stored is 8J
Then, mgh = 8J.
The apple begins to fall and hit the ground, what is the maximum kinetic energy?
Using conservation of energy, as the above is about to hit the ground, the apple is at is maximum speed, and the height then is 0m, so the potential energy at the ground is zero, so all the potential of the apple at the too of the tree is converted to kinetic energy as it is about to hits the ground. Along the way to the ground, both the Kinetic energy and potential energy is conserved, it is notice that at the top of the tree, the apple has only potential energy since velocity is zero at top, and at the bottom of the tree the apple has only kinetic energy since potential energy is zero(height=0)
So,
K.E(max) = 8J
Answer:
2 x 10^-8
Explanation:
the formula of wavelength is
the speed divided by frequency
so you have the speed given = 3.0x10^8m/s
and frequency = 1.5×10^16 Hz
so wavelength = 3.0x10^8m/s / 1.5x10^16 Hz
Answer:
The angular acceleration is 
Explanation:
Given that,
Angular velocity, 
Angular velocity, 
Time t = 10.0 sec
We need to calculate the angular acceleration
Using formula of angular acceleration
Now, we change the angular velocity in rad/s.
Hence, The angular acceleration is
Explanation:
A one-kilogram mass is still a one-kilogram(as mass is an intrinsic property of the object) but the downward force due to gravity, and therefore it's weight, is only one-sixth of what the object would have on the Earth. So man of mass 180 pounds weights only about 30 pounds-force when visiting the moon
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To solve this problem we will apply the concepts related to the calculation of the surface, volume and error through the differentiation of the formulas given for the calculation of these values in a circle. Our values given at the beginning are
The radius then would be
And
PART A ) For the Surface Area we have that,
Deriving we have that the change in the Area is equivalent to the maximum error, therefore
Maximum error:
The relative error is that between the value of the Area and the maximum error, therefore:
PART B) For the volume we repeat the same process but now with the formula for the calculation of the volume in a sphere, so
Therefore the Maximum Error would be,
Replacing the value for the radius
And the relative Error
