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3 years ago

Why is the universe here and why do we exist?

Physics

1 answer:

8_murik_8 [283]3 years ago

8 0

Become a physicist and maybe one day you can tell me.

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Suppose that you take a 10 kg mass on the surface of the earth and then place it on the moon. What will

sergey [27]

Answer:

10 kg

Explanation:

The mass of an object does not change even if the amount of gravtiy changes.

5 0

3 years ago

Tres litros de oxigeno gaseoso a 15 grados centígrados y a presión atmosférica (1atm), se lleva a una presión de 10mm de Hg. ¿ c

lana [24]

Answer:

Three liters of gaseous oxygen at 15 degrees Celsius and at atmospheric pressure (1atm), is brought to a pressure of 10mm Hg. What will be the volume of the gas now if the temperature has not changed?

Explanation:

Given that, the temperature is constant

Then, using gay Lussac law

P1•V1 / T1 = P2•V2 / T2

Since temperature is constant

Then, T1 = T2 = T and they cancels out

So, we are left with

P1•V1 = P2•V2

Given that, .

Initial volume

V1 = 3 litres.

Initial pressure

P1 = 1atm = 101325 Pa

Final pressure

P2 = 10mmHg = 1333.22 Pa

Then, we want to find the final volume V2

Make V2 subject of formula.

V2 = V1•P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litres

So, the final volume is 288 litres.

In Spanish

Dado que la temperatura es constante

Luego, usando la ley gay de Lussac

P1 • V1 / T1 = P2 • V2 / T2

Como la temperatura es constante

Entonces, T1 = T2 = T y se cancelan

Entonces, nos quedamos con

P1 • V1 = P2 • V2

Dado que, .

Volumen inicial

V1 = 3 litros.

Presión inicial

P1 = 1atm = 101325 Pa

Presión final

P2 = 10 mmHg = 1333.22 Pa

Entonces, queremos encontrar el volumen final V2

Hacer V2 sujeto de fórmula.

V2 = V1 • P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litros

Entonces, el volumen final es de 288 litros

8 0

4 years ago

Describe an experiment to find the density of copper turnings using a density bottle amd kerosene

Mrac [35]

BooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooB

3 0

3 years ago

A 30-kg child stands at one end of a floating 20-kg canoe that is 5.0-m long and initially at rest in the water. The child then

Yuliya22 [10]

Answer:

The canoe move 3 m in water.

Explanation:

Given that,

Mass of the child, m = 30 kg

Mass of canoe, M = 20 kg

Length of canoe, L = 5 m

Since initially the boat is floating, its center of mass was at rest. So, when child moves on the boat from one end to the other end, the boat moves in opposite direction in such a way that the displacement of their center of mass remains at rest.
Let x be the displacement of canoe in opposite direction to the motion of child, therefore displacement of child is L - x

So, the displacement of the center of mass is given by :

$d_{cm}=\dfrac{m(L-x)-Mx}{m+M}\\\\0=\dfrac{m(L-x)-Mx}{m+M}\\\\m(L-x)-Mx=0\\\\30(5-x)-20x=0\\\\x=3\ m$

So, the canoe move 3 m in water.

5 0

3 years ago

Shock best describes the current model of the atom ?

const2013 [10]

Answer:

IDK?//

Explanation:

8 0

3 years ago