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4 years ago

Why is life unlikely to be found on the surface of Mars today?

Physics

1 answer:

EleoNora [17]4 years ago

7 0

Answer:

The disappearance of water made the planet dry and barren

Explanation:

Mars was made uninhabitable when its surface water was absorbed into the planet’s crust

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Convertir 500 f a grado celsios

Allushta [10]

Answer:

260° C

Explanation:

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3 years ago

Read 2 more answers

A small, single engine airplane is about to take off. The airplane becomes airborne, when its speed reaches 161.0 kmph. The cond

lukranit [14]

Answer:

384.6 m

Explanation:

The length of the runway airport should be long enough to accommodate the aircraft during its acceleration from rest to 161 km/h at rate of 2.6 m/s. We can use the following equation of motion to solve for this:

$v^2 - v_0^2 = 2a\Delta s$

where v0 = 0 m/s is the initial velocity of the airplane when it start accelerating, v = 161 km/h = 161*1000*(1/60)(1/60) = 44.72 m/s is the airborn speed, a = 2.6 m/s2 is the acceleration, and $\Delta s$ is the distance of the runway, which we care looking for

$44.72^2 - 0 = 2*2.6\Delta s$

$\Delta s = 44.72^2/(2*2.6) = 384.6 m$

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4 years ago

Let's say you are on the third story of an apartment building that has a swimming pool. For some insane reason you think it is a

labwork [276]

Answer:

To make it into the pool you must run and jump at

$\displaystyle v_o=x.\sqrt{\frac{g}{2y}}$

Explanation:

Horizontal Launch

When an object is thrown with a specified initial speed in the horizontal direction, it describes a curved path that finishes when it hits the ground level after traveling certain horizontal distance x and a vertical height y from the launching point. The horizontal speed is always constant and the vertical speed increases due to the effect of gravity. It can be found that the horizontal distance reached by the object when launched at an initial speed in a given time t is

$x=v_o.t$

And the vertical distance is

$\displaystyle y=\frac{g.t^2}{2}$

If t is the total flight time, then x and y are maximum and we can find a relation between them. Solving for t in the first equation

$\displaystyle t=\frac{x}{v_o}$

Substituting in the second equation

$\displaystyle y=\frac{g}{2}\left ( \frac{x}{v_o}\right )^2$

Rearranging

$\displaystyle \left ( \frac{v_o}{x}\right )^2=\frac{g}{2y}$

Solving for $v_o$

$\displaystyle v_o=x.\sqrt{\frac{g}{2y}}$

There are many applications for the horizontal launch. One common situation is when someone wants to drop something on certain terrain at a specific approximate point when traveling in a plane at a given height. Once the object is left fall, it has the same speed as the plane, so the plane speed can be estimated to make the best possible launch, or given that speed, we can know in advance where the object will reach ground level

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3 years ago

Complete this problem so that it can be solved using the concept listed Angela is playing basketball

castortr0y [4]

A. Acceleration that’s the answer I think so

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3 years ago

45. What is the wovelength of a 30. Hertz periodic

Leviafan [203]

The wavelength is 2m.

Hence, Option c) 2m is the correct answer

Given that;