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Vlad [161]
3 years ago
15

A book falls of the table and hits the floor. Is work done? Why?​

Physics
2 answers:
morpeh [17]3 years ago
6 0

<u>Yes, work is done when a book falls of the table.</u>

This is because:

When the book falls, it's potential energy is converted into kinetic energy.   As it reaches the floor down, this kinetic energy is converted to heat energy and sound energy due to the impact.

When a force is imposed on an object to cause displacement of that object, work is done on that object. For a force to do work on an object, there should be a displacement and this force should cause the displacement. So here, since the book falls from the table and causes the displacement of the book from the table to the floor. It is said that work is done.

Work can be given by the formula:

W = F • d

where F is the force and d is the displacement.

prohojiy [21]3 years ago
6 0

Answer:

potential energy

Explanation:

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gladu [14]
<span>a. The magnitude of the vector is doubled as well. Let's say we have a 2-dimensional vector with components x and y. It's magnitude lâ‚ is given by: lâ‚ = âš(x² + y²) If we double the components x and y, the new magnitude lâ‚‚ is: lâ‚‚ = âš((2x)² + (2y²)) With a bit of algebra... lâ‚‚ = âš(4x² + 4y²) lâ‚‚ = âš4(x² + y²) lâ‚‚ = 2âš(x² + y²) We can write the new magnitude lâ‚‚ in terms of the old magnitude lâ‚. lâ‚‚ = 2lâ‚ Therefore, the new magnitude is double the old one. It should be clear that this relationship applies to 3D (and 1D) vectors as well. b. The direction angle is unchanged. The direction angle θ₠for a 2-dimensional vector is given by: θ₠= arctan(y / x) If we double both components, we get: θ₂ = arctan(2y / 2x) θ₂ = arctan(y / x) θ₂ = θ₠The new direction angle is the same as the old one.</span>
7 0
4 years ago
The momentum of an isolated system is conserved A) only in inelastic collisions. B) only in elastic collisions. C) in both elast
vovangra [49]

Answer:

B

Explanation:

because it change heat with the surrounding

8 0
3 years ago
A punter wants to kick a football so that the football has a total flight time of 3.7 s and lands 56m away (measured along the g
Irina18 [472]

The maximum height is 16.8 m

Explanation:

In order to find the maximum height reached by the football, we can just analyze its vertical motion.

The vertical motion of the ball is a free  fall motion, affected only by the force of gravity. So it is a uniformly accelerated motion, and we can use suvat equations.

First of all, we notice that the motion of the ball is symmetrical, so the time taken to reach the maximum height is equal to the time needed to fall down: Since the total time of flight is

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It means that the time to reach the maximum height is

t=\frac{T}{2}=\frac{3.7}{2}=1.85 s

We can now find the maximum height reached using the equation:

s=vt-\frac{1}{2}at^2

Where:

s is the vertical displacement (the maximum height)

v = 0 is the velocity of the ball at the maximum height

t = 1.85 s is the time

a=g=-9.8 m/s^2 is the acceleration of gravity

Solving for s,

s=-\frac{1}{2}(-9.8)(1.85)^2=16.8 m

Learn more about free fall motion here:

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6 0
3 years ago
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Answer:

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Explanation:

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Salsk061 [2.6K]

Answer:

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Explanation:

8 0
4 years ago
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