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2 years ago

8

What is the range of g?

2 answers:

olganol [36]2 years ago

7 0

D it’s connected with 6

Simora [160]2 years ago

6 0

D because your x value is 6

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Slope intercept of (1,1) and (0,7)

Sonja [21]

Answer:

$\boxed {m = -6}$

Step-by-step explanation:

Use the <u>Slope Formula</u> to help you determine the slope of the following two points:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

(Where $(x_{1}, y_{1})$ is the first point and $(x_{2}, y_{2})$ is the second point)

-Apply both points onto that formula:

$(x_{1}, y_{1}) = (1, 1)$

$(x_{2}, y_{2}) = (0, 7)$

$m = \frac{7 - 1}{0 - 1}$

-Solve:

$m = \frac{7 - 1}{0 - 1}$

$m = \frac{6}{-1}$

$\boxed {m = -6}$

3 0

3 years ago

6. Find the missing length. Round the the nearest tenth

DerKrebs [107]

Answer:

6. 10 7.100

Step-by-step explanation:

that is the answer

5 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

3 years ago

I need to know the steps to simplify 15.7 + (-3.45)

faust18 [17]

U call it keep change change. keep 15.7. change it to subtract and change -3.45 to just 3.45 (positive not negative)

5 0

3 years ago

Read 2 more answers

Which equation represents the line whose slope is 1/2 and whose y-intercept is 5

expeople1 [14]

Answer:

y=1/2x+5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers