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2 years ago

What is the mass of 2.15 liters of N2 gas at STP?

Chemistry

2 answers:

Musya8 [376]2 years ago

5 0

Explanation: molar mass of N2=28

Volume occupied at stp=22.4 so 28/22.4=1.25 so mass nitrogen will be 56 multiply 1.25 =70g

IgorLugansk [536]2 years ago

4 0

Answer: 2.68 grams

Explanation:

According to avogadro's law, 1 mole of the substance occupies 22.4 liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

1 mole of $N_2$ weighs 28 grams.

Also 1 mole of $N_2$ occupies 22.4 Liters.

Thus 22.4 L $N_2$ weigh = 28 grams

2.15 L of $N_2$ weigh = $\frac{28}{22.4}\times 2.15=2.68g$

Thus the mass of nitrogen gas is 2.68 grams.

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Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

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$\Rightarrow \frac{dA}{A}=kdt$

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$\Rightarrow A=Ce^{kt}$ [ $e^{c_1}=C$ ]

The initial condition is A(0)= A₀,

$\therefore A_0=Ce^{0.k}$

$\Rightarrow C=A_0$

$\therefore A=A_0e^{kt}$ .........(1)

Given that the $Pb_{209}$ has half life of 3.3 hours.

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$\frac12A_0=A_0e^{k\times3.3}$

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$\Rightarrow k=\frac{ln \frac12}{3.3}$

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

$\therefore 0.2=1e^{(-0.21)\times t}$

$\Rightarrow e^{-0.21t}=0.2$

$\Rightarrow -0.21t= ln(0. 2)$

$\Rightarrow t= \frac{ln (0.2)}{-0.21}$

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

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