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Hitman42 [59]
3 years ago
10

This one as well please

Mathematics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

1/11

Step-by-step explanation:

If there are 11 counters and there's only 1 white one, that makes it to where there's only a 1 in 11 chance of you choosing that one white counter.

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Use the equation to predict how many glasses with 9
cluponka [151]

Answer:

Bella can sell 13.78 glasses with 9 pieces of bling.

Step-by-step explanation:

Given the function

y=1.36x+1.54

  • As pieces of the bling are represented on the x-axis, and the number of glasses is represented on the y-axis.

Given that the number of pieces of bling = x = 9

Thus,

y = 1.36x+1.54

 = 1.36(9)+1.54

 =12.24+1.54

 =13.78

Thus, Bella can sell 13.78 glasses with 9 pieces of bling.

8 0
3 years ago
Tập nghiệm S của bất phương trình : /4x-3/< 9
avanturin [10]

4x -3 < 9

⇔4x < 9 + 3

⇔4x < 12

⇔x < 12/4

⇔x < 3

6 0
3 years ago
Can someone help with this math question please
alexandr1967 [171]
The best choice is
  B.

_____
The black triangle is on the end of one of the rectangular faces, the end that meets up with the double line on the triangular base.

6 0
4 years ago
Write out each step of the 3-step test for continuity for the following functions at the given point. If the function is discont
balandron [24]

If we simply substitute the value x=2 in the expression we have

f(2) = \dfrac{4-12+8}{4-2-2} = \dfrac{0}{0}

which is undefined.

But if we factor both numerator and denominator, we have

f(x)=\dfrac{x^2-6x+8}{x^2-x-2} = \dfrac{(x-2)(x-4)}{(x+1)(x-2)}

Since we are studying the limit as x approaches 2, we can assume that x is not 2. In this case, we can simplify the (x-2) parenthesis, and the expression becomes

f(x)=\dfrac{x-4}{x+1}

And we can evaluate this at 2 with no problems:

f(2) = \dfrac{2-4}{2+1} = -\dfrac{2}{3}

So, we have

\displaystyle \lim_{x\to 2}f(x) = -\dfrac{2}{3}

This means that in this case both left and right limits exist and are the same, so the limit exists, but the function is not defined at x=2. This is a removable discontinuity, because we can define the function as its limit, and we have a continuous function at x=2:

f(x) = \begin{cases}\dfrac{x^2-6x+8}{x^2-x-2} &\text{if }x \neq 2\\ -\frac{2}{3} &\text{if }x = 2\end{cases}

8 0
4 years ago
If 0 is an angle in standard position and its terminal side passes
Gre4nikov [31]

Answer:-27/7

Step-by-step explanation:

3 0
3 years ago
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