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podryga [215]
3 years ago
7

How could you safely determine if a base is stronger than an acid?

Chemistry
1 answer:
expeople1 [14]3 years ago
6 0
You should never taste anything in a lab.
Litmus paper will only tell you whether it is an acid or a base, not how strong it is a hydrogen test only works with acids.
You can get a serious burn from touching strong acids and bases and it doesn't give an objective measure of the strength.
The only one that is left is conductivity. This is safe and rather reliable, because the "strength" of an acid or a base depends on how much it dissociates. Hence more dissociation means greater conductivity.
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Answer:

D. To ensure the cooling process is not affected by surrounding temperature

Explanation:

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6 0
2 years ago
In which of the pairs listed below are both compounds strong electrolytes? Are any strong acids or bases?
Ganezh [65]
<h3>Answer:</h3>

NaCl and Sr(OH)2

<h3>Explanation:</h3>
  • An electrolyte is a substance that is either in molten or aqueous form that can be decomposed by passing an electric current through it.
  • Electrolytes are classified as either strong electrolytes or weak electrolytes.
  • Strong electrolytes are either strong bases or acids which completely ionizes to give mobile ions which are responsible for conduction of electricity.
  • NaCl is a salt and Sr(OH)₂ is a strong base, both are strong electrolytes.
5 0
3 years ago
How to find limiting reagent
Nookie1986 [14]
The reagent which limits the reaction is called limiting reagents.

____

For example:- N2+3H2gives 2NH3.so here nitrogen limits the reaction.

3 0
2 years ago
Read 2 more answers
it takes 463 kJ/mol to break an oxygen-hydrogen single bond. calculate the maximum wavelength of light for which an oxygen-hydro
Marianna [84]

Answer:

  • <u>2.59 × 10⁻⁷ m  = 259 nm</u>

Explanation:

You need to calculate the wavelength of a photon with an energy equal to 463 kJ/mol, which is the energy to break an oxygen-hydrogen atom.

The energy of a photon and its wavelength are related by the Planck - Einstein equation:

  • E = hν,

Where:

  • E = energy of a photon,
  • h = Planck constant (6.626 × 10⁻³⁴ J . s) and
  • ν = frequency of the photon.

And:

  • ν = c / λ

Where:

  • c = speed of light (3.00 × 10⁸ m/s in vacuum)
  • λ = wavelength of the photon

Thus, you can derive:

  • E = h c / λ

Solve for λ:

  • λ = h c / E

Before substituting the values, convert the energy, 463 kJ/ mol, to J/bond

  • 463 kJ/ mol × 1,000 J/kJ × 1 mol / 6.022 × 10 ²³ atom × 1 bond / atom

       = 7.69×10²³ J / bond

Substitute the values and use the energy of one bond:

  • λ = 6.626 × 10⁻³⁴ J . s × 3.00 × 10⁸ m/s / 7.69×10²³ J = 2.59 × 10⁻⁷ m

The wavelength of light is usually shown in nanometers:

  • 2.59 × 10⁻⁷ m × 10⁹ nm / m = 259 nm ← answer
6 0
3 years ago
Explain how you can use an atoms mass number and atoic number to determine the number of protrons electrons and neutrons in the
VMariaS [17]
Simple!

Atomic number= number of protons AND number of electrons (in an atom)

Mass number= number of neutrons


7 0
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