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fenix001 [56]
3 years ago
11

Why is conical flask used in the freezing point of naphthalene activity?

Chemistry
1 answer:
SpyIntel [72]3 years ago
6 0

Answer:

D. To ensure the cooling process is not affected by surrounding temperature

Explanation:

The conical flask acts as a <u>t</u><u>e</u><u>m</u><u>p</u><u>e</u><u>r</u><u>a</u><u>t</u><u>u</u><u>r</u><u>e</u><u> </u><u>j</u><u>a</u><u>c</u><u>k</u><u>e</u><u>t</u><u>.</u>

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Antimony has two naturally occurring isotopes. Their abundance is given in the pic attached below
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3 years ago
If a solution containing A+ ions and a solution containing B- ions have just been mixed and [A+][B-] is greater than Ksp of AB,
frozen [14]

Answer:

Explanation:

In the solution of AB , they are split  to give ions as follows

AB ⇄ A⁺ + B⁻

Product of concentration of A⁺ and B⁻ in saturated solution of AB is constant .

This is called Ksp

Ksp = [A⁺] [ B⁻]

If product of concentration of A⁺  and B⁻ exceeds Ksp , the equilibrium shifts to the left side and excess ions come out of solution in the form of precipitate. So second option is the answer.

4 0
3 years ago
The density of lead is 11.4g/cm3. What volume, in ft3, would be occupied by 10.0 g of lead?
yawa3891 [41]

Answer:

3.10×10¯⁵ ft³.

Explanation:

The following data were obtained from the question:

Density (D) of lead = 11.4 g/cm³

Mass (m) of lead = 10 g

Volume (V) of lead =.?

Density (D) = mass (m) / Volume (V)

D = m/V

11.4 = 10 / V

Cross multiply

11.4 × V = 10

Divide both side by 11.4

V = 10 / 11.4

V = 0.877 cm³

Finally, we shall convert 0.877 cm³ to ft³. This can be obtained as follow:

1 cm³ = 3.531×10¯⁵ ft³

Therefore,

0.877 cm³ = 0.877 cm³ × 3.531×10¯⁵ ft³ /1 cm³

0.877 cm³ = 3.10×10¯⁵ ft³

Thus, 0.877 cm³ is equivalent to 3.10×10¯⁵ ft³.

Therefore, the volume of the lead in ft³ is 3.10×10¯⁵ ft³.

7 0
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What was the scientific basis for the unit amu
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Structure of isobutyl formate
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Answer:

Isobutyl formate (2-methylpropyl methanoate) is an organic ester with the chemical formula C5H10O2. Used for flavor and fragrance because of its odor.

Explanation:

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