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pashok25 [27]
4 years ago
12

What 480nin. as a fraction

Mathematics
1 answer:
ser-zykov [4K]4 years ago
6 0
<span>480/1 hope this help</span>
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Suppose you take a survey of all the schools in your state. What would you expect the relationship between the number of student
Slav-nsk [51]
I think the best option would be C
7 0
4 years ago
Solve using Pythagoras Theorem (please)​
aleksklad [387]

Answer:

HA = 16.2 m

DE = 17 m

Step-by-step explanation:

From the base of the cuboid, HDA will form a right angle triangle, where;

DA = 15 m

HA = 6 m

HA is the hypotenuse

Using pythagoras theorem;

HA = √(15² + 6²)

HA = √(225 + 36)

HA = √261

HA = 16.155 m

Approximating to 1 decimal place gives;

HA = 16.2 m

Similarly, HDE will also form a right angle triangle.

Thus;

DE = √((HD)² + (HE)²)

HD = 16.2 m

HE = 5 m

Thus;

DE = √(16.2² + 5²)

DE = 16.95 m

Approximating to 1 decimal place gives

DE = 17 m

3 0
3 years ago
In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o
ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = \frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}

X = 0.13

s = \sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for t_{6,0.005} is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = t_{6,0.005} . \frac{s}{\sqrt{N} }

E = 3.707. \frac{0.029}{\sqrt{7} }

E = 0.041

The interval will be:  

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0
4 years ago
What is the factored form of the expression? k2 – 9h2
VARVARA [1.3K]
The factored form of this expression would be :

(k-3h)(k+3h).
4 0
3 years ago
Read 2 more answers
A cone has a height of 8.4 centimeters and a base with a radius of 5.2 centimeters. what is the volume of the cone??
wlad13 [49]
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3

</span></span></span></span>
<span>Cone Volume = (<span>π<span> • (5.2)² •<span> 8.4) ÷ 3

</span></span></span></span><span><span><span><span>Cone Volume = (3.14159 * </span>27.04 * 8.4) / 3</span> </span> </span>

<span><span><span><span>Cone Volume = </span>237.85606208 </span> </span> </span>


3 0
3 years ago
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