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Marizza181 [45]
3 years ago
13

a person's lung pressure as recorded by a mercury manometer is 90 mm Hg.Express this pressure in SI units​

Physics
1 answer:
Sidana [21]3 years ago
4 0

Answer:

11970 pa

Explanation:

A millimetre of mercury is a manometric unit of pressure, formerly defined as the extra pressure generated by a column of mercury one millimetre high, and currently defined as exactly 133.322387415 pascals so if 1 mmHg is 133 pa  90mmHg is 11970 aprox

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A Go Kart (m = 35 kg) has a top speed of 12 m/s . A student traveling at top speed locks the brake to avoid hitting a bus after
Sergeu [11.5K]

Answer:

350 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of Go Kart = 35 kg

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Force (F) =?

Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Final velocity (v) = 0 m/s

Acceleration (a) =.?

v² = u² + 2as

0² = 12² + (2 × a × 7.2)

0 = 144 + 14.4a

Collect like terms

0 – 144 = 14.4a

– 144 = 14.4a

Divide both side by 14.4

a = – 144 / 14.4

a = – 10 m/s²

The negative sign indicate that the Go Kart is decelerating when the brake was applied.

Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:

Mass (m) of Go Kart = 35 kg

Acceleration (a) = 10 m/s

Force (F) =?

F = ma

F = 35 × 10

F = 350 N

Thus, the Go Kart has a force of 350 N when the student locked the brake.

7 0
3 years ago
Light with a wavelength of 600 nm is incident on a gemstone made of cubic zirconia (ᡦ =2.18) from air. The light makes an angle
gregori [183]

Answer:

500 THz .

Explanation:

Velocity of light in air = 3 x10⁸ m /s

wave length of light = 600 nm

= 600 x 10⁻⁹ m

= 6 x 10⁻⁷ m

frequency in air  = velocity in air  / wave length in air

= 3 x 10⁸ /  6 x 10⁻⁷

= .5 x 10¹⁵ Hz

= 5 x 10¹⁴Hz

= 500 x 10¹² Hz

= 500 THz

When light enters the medium of gem , its wavelength and velocity changes in such a way that its frequency remains constant. So in the medium of gem also its frequency remains 500 THz .

3 0
3 years ago
Which of the following is a sign of Anorexia Nervosa?
Alla [95]
B is the correct answer because anorexia nervosa is an eating disorder in which the victim refrains from eating due to body image insecurities.
4 0
3 years ago
An electron is moving east in a uniform electric field of 1.55 N/C directed to the west. At point A, the velocity of the electro
valkas [14]

Answer:

Final velocity of electron, v=6.45\times 10^5\ m/s    

Explanation:

It is given that,

Electric field, E = 1.55 N/C

Initial velocity at point A, u=4.52\times 10^5\ m/s

We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :

v^2=u^2+2as........(1)

a is the acceleration, a=\dfrac{F}{m}

We know that electric force, F = qE

a=\dfrac{qE}{m}

Use above equation in equation (1) as:

v^2=u^2+\dfrac{2qEs}{m}

v^2=(4.52\times 10^5\ m/s)^2+2\times \dfrac{1.6\times 10^{-19}\ C\times 1.55\ N/C}{9.1\times 10^{-31}\ kg}\times 0.395\ m

v = 647302.09 m/s

or

v=6.45\times 10^5\ m/s

So, the final velocity of the electron when it reaches point B is 6.45\times 10^5\ m/s. Hence, this is the required solution.

3 0
3 years ago
Do you think antiseptic creams and lotions play an important part in our day<br>to day life? ​
timama [110]

Answer:

no, otherwise they just cause a side effect on our lives

8 0
3 years ago
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