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antoniya [11.8K]
3 years ago
11

An action potential is regarded as an example of a positive feedback. Which of the following examples below best illustrates the

positive feedback aspect of an action potential?
Potassium permeability is about 25 times greater than sodium ions.

Voltage gated potassium ion channels open slowly and remain open long enough to cause hyperpolarization.

The sodium potassium pump consistently moves ions as long as ATP is available, and regardless of membrane potential changes.

A threshold stimulus will cause the opening of voltage gated sodium ion channels that will cause further depolarizing stimulus.

This stimulus will open still more voltage gated sodium ion channels.
Chemistry
1 answer:
saul85 [17]3 years ago
4 0

Answer:

A threshold stimulus will cause the opening of voltage gated sodium ion channels that will cause further depolarizing stimulus.This stimulus will open still more voltage gated sodium ion channels.

Explanation:

Action potential: It occurs when the potential of a membrane, of a specific cell location rapidly falls and raises. This depolarization stimuli later cause adjacent location to similarly depolarize. It is produce by the special types of voltage gated ion channels present in the cell's plasma membrane.

These channels are closed when the membrane potential near resting potential of the cell which is also called negative potential, but they fastly starts to open if the membrane potential increase to a defined threshold voltage, and depolarizing the potential of transmembrane.

When the channels are open, they allow sodium ions inward flow, which cause the changes in electrochemical gradient and producing further raise in the membrane potential. This then cause more channels to open.

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Answer:

Trial     Number of moles

           

  1          0.001249mol

  2         0.001232mol

  3          0.001187 mol

Explanation:

To calculate the <em>number of moles of tritant</em> you need its<em> molarity</em>.

Since the<em> molarity</em> is not reported, I will use 0.1000M (four significant figures), which is used in other similar problems.

<em>Molarity</em> is the concentration of the solution in number of moles of solute per liter of solution.

In this case the solute is <em>NaOH</em>.

The formula is:

          Molarity=\dfrac{\text{Number of moles of solute}}{\text{Volume of solution in liters}}

Solve for the <em>number of moles:</em>

          \text{Number of moles}=Molarity\times Volume\text{ }in\text{ }liters

Then, using the molarity of 0.1000M and the volumes for each trial you can calculate the number of moles of tritant.

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1          12.49       0.01249        0.01249liters × 0.1000M = 0.001249mol

2         12.32      0.01232         0.01232liters × 0.1000M = 0.001232mol

3          11.87       0.01187         0.01187liters × 0.1000M = 0.001187 mol

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