Answer is: the number of ions produced in the dissociation of aluminium fluoride is 4.
<span>
Chemical dissociation of aluminium fluoride in
water:
AlF</span>₃(aq) →
Al³⁺(aq) + 3F⁻(aq).<span>
There are four ions, one aluminium cation and
three fluoride anions.
Aluminium has oxidation +3, because it lost
three electrons, to have electron configuration as noble gas neon and fluorine has oxidation -1, because it gain one electron to </span>have electron configuration as noble gas neon.
For every 2 Mol NaOH you would get 1 Mol N2H4
_Brainliest if helped!
Neon, as it is of smaller size. U can take the dipole strength as proportional to Charge/Radius , they have "same charge" but different radius.
