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natali 33 [55]
2 years ago
6

Which of the following combinations of information would allow you to calculate concentration in ppmv? Check all that apply. mol

es of solute and mass of solution moles of solute, mass of solution, and density of solution mass of solute, density of solute, and volume of solution volume of solute, mass of solution, and density of solution
Chemistry
1 answer:
kakasveta [241]2 years ago
3 0

Answer:

Explanation:

-mass of solute, density of solute, and volume of solution

-volume of solute, mass of solution, and density of solution

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The elements mercury and bromine are both liquids at room temperature, but mercury is considered a metal, and bromine is conside
prohojiy [21]

Answer:

At room temperature, mercury and bromine are of fluid consistency, it is because their melting or melting temperature is very low, so low that it reaches room temperature.

Compared to mercury and other metals, the more traditional metals have much higher melting temperatures.

On the other hand, bromine is not a metal, since it does not have the ability to oxidize with the presence of oxygen and also does not give up electrons.

Explanation:

Mercury in the periodic table is Hg, and bromine is Br

7 0
2 years ago
How many moles of carbon dioxide gas, co2, are there in 2.94 l of this gas at stp
Colt1911 [192]

Pls go through this solution

7 0
3 years ago
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How can you make hard water into soft water ?
DENIUS [597]

Answer:

hey...

Explanation:

Sodium carbonate (Na2CO3), also known as washing soda, can soften both temporary and permanent hard water.

6 0
3 years ago
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Determine the temperature of 1.42 mol of a gas contained in a 3.00-L container at a pressure of 123 kPa.
Schach [20]

Answer:

31.2K

Explanation:

The following data were obtained from the question:

n = 1.42 mol

V = 3L

P = 123 kPa = 123000Pa

Recall: 101325Pa = 1atm

123000Pa = 123000/101325 = 1.21atm

R = 0.082atm.L/Kmol

T =?

Using the ideal gas equation PV = nRT, we can obtain the temperature as follows:

PV = nRT

T = PV/nR

T = (1.21 x 3)/(1.42 x 0.082)

T = 31.2K

8 0
3 years ago
The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product str
iren2701 [21]

Answer:

Explanation:

The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.

C2H4 + HBr ------------------------> C2H5Br.

The chemical species/compounds reacted in the ratio of 1 : 1 : 1. That is one mole of C2H4 reacted with one mole of HBr to give one mole of C2H5Br.

So, we are given; C2H5Br = 58.7 mol%, HBr = 18.3 mol%. Thus, for C2H4, we have [ 100 - (58.7 + 18.3)] = 23 mol%. Therefore, the limiting reagent is HBr.

So, if we have 100 mol/s ;

C2H5Br = 100 × 0.587 = 58.7 mol/s, HBr = 100 × 0.183 = 18.3 mol/s and C2H4 = 100 × 0.23 = 23 mol/s.

Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .

So, 100/158.7 × 30.5 = 192.2.

Also the feed composition in HBr and C2H4 is;

HBr = 77/158.7 = 0.4852, C2H4 = 81.7/158.7 = 0.515.

Therefore, the number of HBr in feed and C2H4 in feed = 160m/s and 200m/s respectively (approx.)

Therefore, the fraction conversion is;

8 0
2 years ago
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