Find the nth term of 14,23,32,41

1 answer:

german3 years ago

8 0

$\\$Let a_n$ be the following sequence: 14, 23, 32, 41, ...\\a_1 = 14 \ \ \ a_2 = 23 \ \ \ a_3 = 32 \ \ \ a_4 = 41\\$Observe that $ a_2 - a_1 = a_3 - a_2 = a_4 - a_3 = 9 =>$ a_n - $Arithmetic progression$=> a_n = 14 + 9(n-1)$

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