Question

Hii:) I need help with qn 1 & please explain if possible too :) , thanks!

Answer 1

1. In the first 1.5 seconds, the lift accelerates from 0 to 3m/s. By definition, the acceleration is the ratio between the change in velocity and the time elapsed to change the velocity.

The change in velocity is $\Delta v = v_{\text{final}}-v_{\text{initial}}=3-0=3$.

The time elapsed is 1.5 seconds, so the acceleration is

$a = \dfrac{3}{1.5}=2$

meters per second squared.

2. We know, from the previous point, that the lift travelled 20m from the first floor. Since it returns to the first floor after the ascent, it must travel again those same 20m, just in reverse (descending instead of ascending). So, the total distance travelled is $20+20=40$ meters.

The displacement, though, is zero, because it measures the distance between the starting and ending point of a certain motion. Since the lift starts and ends its motion at the same place (the first floor), its total displacement is zero.