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alina1380 [7]
3 years ago
10

In a chemical reaction, substances react in a specific ratio. Chemical reactions are used to make many products, including food.

For a company that carries out a chemical reaction to make a product, why would it be important to know the ratio of substances?
Physics
1 answer:
inysia [295]3 years ago
6 0

Answer: “Chemical equations need to be balanced in order to satisfy the law of conservation of matter, which states that in a closed system matter is neither created nor destroyed. There are some things called mole ratios, which are important because mole ratios allow you change moles of a substance to moles of another substance. The mole ratio is the magic that changes from A to B. The mole ratios come from the chemical formula or equation.”

You need to make sure you have an equal balance so that you don’t make a mistake and mess up the reaction. If anything goes minutely wrong, it may alter the substance. Knowing the ratios of substances can help to make the product as expected.

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Jack pushed and pushed, and finally moved the new refrigerator into the kitchen. What is the BEST explanation of what happened?
Anika [276]

Answer:

a

Explanation:

6 0
4 years ago
A 40 kg bear slides, from rest, 14 m down a lodgepole pine tree, moving with a speed of 3.7 m/s just before hitting the ground.
antiseptic1488 [7]

Answer:

A. -5488J

B. 273.8J

C. 372.44N

Explanation:

Given:

m = 40kg

h = 14 m

v= 3.7 m/s

Part(a)

The change in the potential energy of the bear Earth system during the slide

AU = -mgh = -40(9.8) (14) = -5488 J

Part(b)

The kinetic energy of the bear just before hitting the ground is

Ks 1/2 mV^2= (40)(3.7)2 = 547.6 /2 = 273.8J

Part(c)

The change in the thermal energy of the system due to friction is

AEth = fxh=-(AK +AU) = 5488– 273.8 = 5214.2 J

The average frictional force that acts on the sliding bear is

F = Eth / 14= 5214.2/14 =372.44N

4 0
3 years ago
Read 2 more answers
[3 points] Question: Consider a pendulum made from a uniform, solid rod of mass M and length L attached to a hoop of mass M and
aliina [53]

Answer:

I=\frac{4}{3}ML^2+2MR^2+2MRL

Explanation:

We are given that

Mass of rod=M

Length of rod=L

Mass of hoop=M

Radius of hoop=R

We have to find the moment of inertia I of the pendulum about pivot depicted at the left end of the slid rod.

Moment of inertia of rod about center of mass=\frac{1}{12}ML^2

Moment of inertia of hoop about center of mass=MR^2

Moment of inertia of the pendulum about the pivot left end,I=\frac{1}{12}ML^2+M(\frac{L}{2})^2+MR^2+M(L+R)^2

Moment of inertia of the pendulum about the pivot left end,I=\frac{1}{12}ML^2+\frac{1}{4}ML^2+MR^2+MR^2+ML^2+2MRL

Moment of inertia of the pendulum about the pivot left end,I=\frac{1+3+12}{12}ML^2+2MR^2+2MLR

Moment of inertia  of the pendulum about the pivot left end,I=\frac{16}{12}ML^2+2MR^2+2MRL

Moment of inertia of the pendulum about the pivot left end,I=\frac{4}{3}ML^2+2MR^2+2MRL

8 0
4 years ago
Read 2 more answers
imagine that you have a sample of an unknown element and that you know only the elements mass number without directly measuring
Ostrovityanka [42]
If the element's atomic mass is accurate enough you should be able to tell from that , however if it isn't you would most likely want the number of neutrons or electrons contained by the atom.
4 0
3 years ago
What is the impulse of a 3kg object accelerating from rest to 12m/s?
ale4655 [162]
To find the impulse you multiply the mass by the change in velocity (impulse=mass×Δvelocity). So in this case, 3 kg × 12 m/s ("12" because the object went from zero m/s to 12 m/s).

The answer is 36 kg m/s
6 0
3 years ago
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