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podryga [215]
3 years ago
11

Record your model values in the table below

Physics
1 answer:
AlladinOne [14]3 years ago
8 0
There not enough inform here to answer this question
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The potential difference between the plates of an ideal air-filled parallel-plate capacitor with a plate separation of 6.0 cm is
Yanka [14]

Answer:

1000 N/C

Explanation:

Potential difference, V = 60 V

Distance between the plates, d = 6 cm = 0.06 m

The electric field between the plates is given by

E = V / d

E = 60 / 0.06 = 1000 N/C

Thus, the electric filed between the plates is 1000 N/C.

8 0
3 years ago
Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one we
ziro4ka [17]

Answer:

it should be a new moon

Explanation:

4 0
3 years ago
What is the mass of a stone moving at a speed of 15 m/s and having a monument at 7.1 kg meters per second
adell [148]

Answer:

<h3>The answer is 0.47 kg</h3>

Explanation:

The mass of the object given it's momentum and velocity can be found by using the formula

m =  \frac{p}{v}  \\

where

p is the momentum

v is the velocity

We have

m =  \frac{7.1}{15}  \\  = 0.4733333...

We have the final answer as

<h3>0.47 kg</h3>

Hope this helps you

4 0
3 years ago
Please help me whit this question
mariarad [96]

Answer:

Gypsum

Explanation:

Gypsum is a soft sulfate mineral composed of Calcium Sulfate di-hydrate. It is widely used in composition of fertilizer. It is also known as land plaster. On adding gypsum to soil, the quality of soil is improved. It conditions the soil and adds nutrients. The properties of soil is improved. Hence, the correct answer is Gypsum.

Hope this helped:)

pls mark brainlist

6 0
3 years ago
A uniform magnetic field is perpendicular to the plane of a circular loop of diameter 13 cm formed from wire of diameter 2.6 mm
I am Lyosha [343]

Answer:

Rate of change of magnetic field is 3.466\times 10^3T/sec        

Explanation:

We have given diameter of the circular loop is 13 cm = 0.13 m

So radius of the circular loop r=\frac{0.13}{2}=0.065m

Length of the circular loop L=2\pi r=2\times 3.14\times 0.065=0.4082m

Wire is made up of diameter of 2.6 mm

So radius r=\frac{2.6}{2}=1.3mm=0.0013m

Cross sectional area of wire A=\pi r^2=3.14\times0.0013^2=5.30\times 10^{-6}m^2

Resistivity of wire \rho =2.18\times 10^{-8}m

Resistance of wire R=\frac{\rho L}{A}=\frac{2.18\times 10^{-8}\times 0.4082}{5.30\times 10^{-6}}=1.67\times 10^{-3}ohm

Current is given i = 11 A

So emf  e=11\times 1.67\times 10^{-3}=0.0183volt

Emf induced in the coil is e=-\frac{d\Phi }{dt}=-A\frac{dB}{dt}

0.0183=5.30\times 10^{-6}\times \frac{dB}{dt}

\frac{dB}{dt}=3.466\times 10^3=T/sec

8 0
3 years ago
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