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riadik2000 [5.3K]
3 years ago
13

How would you describe the interaction between opposite (N-S or S-N) magnetic pols?

Physics
1 answer:
Oxana [17]3 years ago
8 0
<span>every magnet you interact with on a daily basis has two poles: a north and a south pole. Fridge magnets are permanent ferromagnets, and their magnetic field is generated by the alignment of their internal magnetic domains. A magnet sticks to a fridge not because the "fridge's pole" is opposite in sign to the "magnet pole" - the magnet always has two poles - but rather because the magnetic domains in the iron/steel of the fridge door align with the magnet field created by the permanent magnet, creating a 'new magnet" on the region it touches on the fridge. Both the north and south pole of a magnet will stick to a fridge, as well the side of the magnet containing both north and south poles.</span>
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The table lists the speed of light in four different materials at the same temperature. Through which material would light trave
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You are given two balls that are made from the same rubber. They are also the same size and color. One is hollow and one is soli
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What is the equivalent resistance in a parallel circuit that has the following three resistors: 6.8 ohms, 9.0 ohms, and 15.0 ohm
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3 years ago
A plastic rod of length d = 1.5 m lies along the x-axis with its midpoint at the origin. The rod carries a uniform linear charge
Serga [27]

Answer:

Explanation:

Let the plastic rod extends from - L to + L .

consider a small length of dx on the rod on the positive x axis at distance x . charge on it =  λ dx where  λ is linear charge density .

It will create a field at point P on y -axis . Distance of point P

= √ x² + .15²

electric field at P due to small charged length

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Its component along Y - axis

= dE cosθ where θ is angle between direction of field dE and y axis

= dE x .15 / √ x² + .15²

=  k λ dx  .15 / (x² + .15² )³/²

If we consider the same strip along the x axis at the same position  on negative x axis , same result will be found . It is to be noted that the component of field in perpendicular to y axis will cancel out each other . Now for electric field due to whole rod at point p , we shall have to integrate the above expression from - L to + L

E = ∫  k λ  .15  / (x² + .15² )³/² dx

=  k λ  x L / .15 √( L² / 4 + .15² )

6 0
4 years ago
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