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lozanna [386]
2 years ago
15

A student holds an egg outside of an open window and let's go. The window is 40 meters above the ground and the egg is falling u

nder the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
How far will the egg travel after 2 seconds? Be sure to use the 5 steps to solve the problem. Show which equation you used, what each variable equals, and answer the question in a complete sentence.
Physics
1 answer:
melisa1 [442]2 years ago
5 0

The distance traveled by the egg after 2 seconds is 19.6 m.

The given parameters:

  • <em>Height of the window, h = 40 m</em>

The distance traveled by the egg after 2 seconds is calculated as follows;

h = v_0_y t + \frac{1}{2} gt^2\\\\

where;

  • <em />v_0_y<em> is the initial vertical velocity of the egg = 0</em>
  • <em>g </em><em>is acceleration due to gravity = 9.8 m/s²</em>
  • <em>t </em><em>is the time of motion, = 2 s</em>

h = 0 \ + \ \frac{1}{2} \times 9.8 \times (2)^2\\\\h = 19.6 \ m

Thus, the distance traveled by the egg after 2 seconds is 19.6 m.

Learn more about second equation of motion here: brainly.com/question/7977693

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Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let |a| = 22 lb and |b| = 16 lb. Rou
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Incomplete question as the angle between the force is not given I assumed angle of 55°.The complete question is here

Two forces, a vertical force of 22 lb and another of 16 lb, act on the same object. The angle between these forces is 55°. Find the magnitude and direction angle from the positive x-axis of the resultant force that acts on the object. (Round to one decimal places.)  

Answer:

Resultant Force=33.8 lb

Angle=67.2°

Explanation:

Given data

Fa=22 lb

Fb=16 lb

Θ=55⁰

To find

(i) Resultant Force F

(ii)Angle α

Solution

First we need to represent the forces in vector form

\sqrt{x} F_{1}=22j\\ F_{2}=u+v\\F_{2}=16sin(55)i+16cos(55)j\\F_{2}=16(0.82)i+16(0.5735)j\\F_{2}=13.12i+9.176j

Total Force

F=F_{1}+F_{2}\\ F_{2}=22j+13.12i+9.176j\\F_{2}=13.12i+31.176j

The Resultant Force is given as

|F|=\sqrt{x^{2} +y^{2} }\\|F|=\sqrt{(13.12)^{2} +(31.176)^{2} }\\ |F|=33.8lb

For(ii) angle

We can find the angle bu using tanα=y/x

So

tan\alpha =\frac{31.176}{13.12}\\ \alpha =tan^{-1} (\frac{31.176}{13.12})\\\alpha =67.2^{o}

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