Answer:
v₀ = 60.38 mi / h
With this stopping distance, the starting speed should have been 60.38 mi/h, which is much higher than the maximum speed allowed.
Explanation:
For this exercise let's start by using Newton's second law
Y axis
N-W = 0
N = W
X axis
fr = m a
the expression for the friction force is
fr = μ N
we substitute
μ mg = m a
μ g = a
calculate us
a = 0.620 9.8
a = 6.076 m / s²
now we can use the kinematics relations
v² = v₀² - 2 a x
suppose v = 0
v₀ = 
Ra 2ax
let's calculate
v₀ = 
v₀ = 27.00 m / s
let's slow down to the english system
v₀ = 27.0 m / s (3.28 ft / 1m) (1 mile / 5280 ft) (3600s / 1h)
v₀ = 60.38 mi / h
With this stopping distance, the starting speed should have been 60.38 mi/h, which is much higher than the maximum speed allowed.
Answer:
P =18760.5 Pa
Explanation:
Given that
Volume ,V= 0.0434 m³
Mass ,m= 4.19 g = 0.00419 kg
T= 417 K
If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation
Ideal gas equation P V = m R T
p=Pressure ,V = Volume ,m =mass
T=Temperature ,R=Universal gas constant
Now by putting the values
P V = m R T
For water R= 0.466 KJ/kgK
P x 0.0434 = 0.00419 x 0.466 x 417
P =18.7605 KPa
P =18760.5 Pa
Therefore the answer is 18760.5 Pa
No. You cannot rule out the battery even after the open circuit voltage measurement. The open-circuit voltage may not have changed but the battery's internal resistance may have greatly increased.
Answer:
Because the Moon casts a smaller shadow than Earth does, eclipses of the Sun tightly constrain where you can see them. If the Moon completely hides the Sun, even for a moment, the eclipse is considered total.
Explanation:
