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3 years ago

An object with a momentum of 12 kg m/s is travelling at 3m/s.what is its mass

Mathematics

1 answer:

tekilochka [14]3 years ago

6 0

4 kg because p (momentum) = m • v and p / v = m.
So 12 kg m/s divided by 3 m/s = 4 kg

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What number is 15% of 120

Sergio039 [100]

Answer:

Step-by-step explanation:

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4 years ago

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Use the distributive property with factoring to find the equivalent expression. 24n + 32w = (3n + w)

pashok25 [27]

Answer:

Step-by-step explanation:

24n + 32w = (3n + w)

We're asked to use distributive property, this means that we have to find a way that the given expression on the left hand side is equal to the given incomplete exresssion on the right hand side. In so doing, we're fulfilling the distributive property tag.

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garik1379 [7]

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The third one

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It can't be the first one since the peak is 4 since it is the highest

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3 years ago

If u+v+w=0, show that u x v = v x w = w x u.

Flauer [41]

Take the cross product of both sides of $\mathbf u+\mathbf v+\mathbf w=\mathbf0$ with $\mathbf u,\mathbf v,\mathbf w$ to generate a system of three simultaneous equations.

$(\mathbf u+\mathbf v+\mathbf w)\times\left\{\begin{matrix}\mathbf u\\\mathbf v\\\mathbf w\end{matrix}\right\}=\mathbf0\times\left\{\begin{matrix}\mathbf u\\\mathbf v\\\mathbf w\end{matrix}\right\}$
$\implies\begin{cases}\mathbf u\times\mathbf u+\mathbf u\times\mathbf v+\mathbf u\times\mathbf w=\mathbf0\\\mathbf v\times\mathbf u+\mathbf v\times\mathbf v+\mathbf v\times\mathbf w=\mathbf0\\\mathbf w\times\mathbf u+\mathbf w\times\mathbf v+\mathbf w\times\mathbf w=\mathbf0\end{cases}$
$\implies\begin{cases}\mathbf u\times\mathbf v+\mathbf u\times\mathbf w=\mathbf0\\\mathbf v\times\mathbf u+\mathbf v\times\mathbf w=\mathbf0\\\mathbf w\times\mathbf u+\mathbf w\times\mathbf v=\mathbf0\end{cases}$

since $\mathbf x\times\mathbf x=\mathbf0$ for any vector $\mathbf x$ .

Finally, use the fact that the cross product is anticommutative, i.e. $\mathbf x\times\mathbf y=-\mathbf y\times\mathbf x$ . The conclusion follows.

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