Answer:
0.1g to 0.0000001g hope it helps uu
d = speed x time
distance = 29 x 30
distance = 870m
please mark as BRAINLIEST
In a projectile, the horizontal acceleration is zero. The velocity remains constant at all times. However, the <u>vertical acceleration</u> is -9.81m/s^2.
Hope this helps!
Answer:
F = 1480.77N
Explanation:
In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:
(1)
F: required force = ?
W: weight of the container = 1800N
N: normal force = weigth
α: angle of the incline = 28°
g: gravitational acceleration = 9.8m/s^2
μ: coefficient of friction = 0.4
You solve the equation (1) for F and replace the values of the other parameters:

The required force to push the container for the incline with a constant velocity is 1480.77N