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Bad White [126]
4 years ago
13

A heat engine uses thermal energy flowing from a heat source that is 225k to a cold sink that is 50k. What is the approximate ef

ficiency of that heat engine?
Physics
1 answer:
Arte-miy333 [17]4 years ago
3 0

efficiency of heat engine is given as

\eta = 1 - \frac{T_2}{T_1}

now we know that

T_2 = temperature of sink

T_1 = temperature of high temperature source

now it is given that

T_2 = 50 k

T_1 = 225 k

now from the given equation we have

\eta = 1 - \frac{50}{225}

\eta = 0.78

so efficiency of heat engine will be 78%

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An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the
alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

X=V_{o}*t + \frac{a*t^{2}}{2}   Replacing the known values:

1500=6t+0.9*t^{2}    Solving for t we get 2 possible answers:

t1 = -44.3s   and t2 = 67.7s    Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

8 0
3 years ago
The amplitude of the voltage across an inductor can be greater than the amplitude of the generator EMF in an AC RLC circuit. Con
Degger [83]

Answer:

VL=2107.6v

Explanation:

at resonance xc=xL

1/wc = wL

z=R

because sqr(R^2+(xL-xc))

^

(xL=xc)

V/R=I

90/28.9=3.1142A

w=1/sqr(1.31×(2.86×10^-6))=516.63

xL= wL

xL= 516.63×1.31=676.785

VL=3.1142×676.785

VL=2107.6v

4 0
3 years ago
a current exists whenever electric charges move. if δq is the net charge that passes through a surface during a time period δt,
mr Goodwill [35]

The average current during the given time interval is δq/δt.

Based on their motion, charges are of two types- charges at rest and charges in motion.

The charges at rest do not produce an electric current but the moving charges produce an electric current.

The attached diagram represents the flow of charges which leads to the production of electric current.

The flow of current is not always steady, so we define it in the form of average current for a particular duration of time.

The relation between average current, the amount of charge passing through a surface, and the time taken in doing so is given by the following equation,

I = δq/δt

Here, I represent the average current during a particular duration of time, δq is the amount of net charge that passes through a surface during a period δt.

Hence, the average current during this time interval is δq/δt.

To know more about "Electric current", refer to the following link:

brainly.com/question/2264542?referrer=searchResults

#SPJ4

5 0
2 years ago
You are given a cylinder of outer radius 3.27 cm and length of 11.5 cm. along the axis of the cylinder is a hole of diameter 2.4
natta225 [31]
  <span> Required Volume (V) = Area of the base * Height

Area of the base = Pi [ 3.27² - (2.47/2)² ] since 2.47 is diameter and not radius. = Pi ( 9.981675 )

Therefore Volume (V) = Pi ( 9.981675) * 15.9 = 498.5978739 cm³ = 498.6 cm³.</span>
7 0
3 years ago
A rope is tied to a tree 4.5 feet from the ground and then run through a pulley hooked to a vehicle 33 feet from the tree. If a
Angelina_Jolie [31]

Answer:

The vehicle displacement is 9.90 feet.

Explanation:

Given that,

Height of tree = 4.5 feet

Distance = 33 feet

According to figure,

We need to calculate the value of l

Using Pythagorean theorem

l=\sqrt{(33)^2+(4.5)^2}

We need to calculate the vehicle displacement

Using horizontal component

Vehicle displacement =horizontal component of pulled rope

Vehicle\ displacement= d\cos\theta

Where, \theta is angle between rope and ground

d = pulled length of rope

Vehicle\ displacement=10\times\dfrac{33}{\sqrt{(33)^2+(4.5)^2}}

Vehicle\ displacement=9.90\ feet

Hence, The vehicle displacement is 9.90 feet.

3 0
3 years ago
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