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Naya [18.7K]
3 years ago
10

When experimenting with the photoelectric effect, what factor of light affected the kinetic energy of the electrons emitted from

metal?
a)Amplitude of light.
b)Frequency of light.
c)Intensity of light.
d)The amount of time it was exposed to light.
Physics
1 answer:
Shtirlitz [24]3 years ago
5 0

Answer:

c

Explanation:

intensity of light in the

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Answer:

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The resistance of a light bulb that draws a current of 2 a when connected t a 12 v battery is?
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Explanation:

V = I *R

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2. A 1.54 kΩ resistor is connected to an AC voltage source with an rms voltage of 240 V.
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(a) The maximum potential difference across the resistor is 339.41 V.

(b) The maximum current through the resistor is 0.23 A.

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(d)  The average power dissipated by the resistor is 38.4 W.

<h3>Maximum potential difference</h3>

Vrms = 0.7071V₀

where;

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V₀ = Vrms/0.7071

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V₀ = 339.41 V

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I(rms) = V(rms)/R

I(rms) = (240)/(1,540)

I(rms) = 0.16 A

<h3>maximum current through the resistor </h3>

I₀ = I(rms)/0.7071

I₀ = (0.16)/0.7071

I₀ = 0.23 A

<h3> Average power dissipated by the resistor</h3>

P = I(rms) x V(rms)

P = 0.16 x 240

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Learn more about maximum current here: brainly.com/question/14562756

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