Answer:
d) precipitation
Hope it helps you
And if you want to, pls mark it as the brainliest answer
Answer:
v = 30.39 m/s
Explanation:
given,
mass of glider,M = 680 Kg
mass of the skydiver, m = 68 Kg
horizontal velocity,V = 30 m/s
when skydiver releases, velocity,v = 30 m/s
velocity if the glider,v' = ?
use the conservation of momentum
M V = m' v' + m v
m' = 680-68 = 612 Kg
680 x 30 = 612 x v + 60 x 30
612 v = 18600
v = 30.39 m/s
since the skydiver's speed will be the same as before release
The glider should continue to travel at 30.39 m/s since there are no external forces acting on it
Answer:
false
Explanation:
some can be harmful but not all
The static friction exerted on the block by the incline is
.
The given parameters;
- <em>mass of the block, = M</em>
- <em>coefficient of static friction in section 1, = </em>
<em /> - <em>angle of inclination of the plane, = θ</em>
<em />
The normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;

Thus, the static friction exerted on the block by the incline is 
Learn more here:brainly.com/question/17237604
Answer:
-3m+7m = 4m
Explanation:
As he walks south, he is going down 3m (-3m). Then he walks up 7m (+7m).
You subtract the final position from the initial position to get displacement.
7m - 3m = 4m