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pentagon [3]
3 years ago
8

A light-year is the distance light travels in one year, at a speed = 2.998 x 10^8 m/s.

Physics
1 answer:
Drupady [299]3 years ago
8 0
A. <span>7.57×10^16 m
B. </span><span>6.31×10^4 AU/ly
C. </span><span>7.19 AU/h</span>
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Which event causes tides
Reptile [31]

Answer:

High tides and low tides are caused by the Moon.

Explanation:

The Moon's gravitational pull generates something called the tidal force.

3 0
3 years ago
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Juli2301 [7.4K]

The speed at which the objects were attracted to each other determined by the gravitational pull.

<h3>What is gravity?</h3>

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity or gravitational pull.

The gravitational force, Fg is the attractive force exerted by the Earth on the object that is equal to the mass of the object times the gravitational acceleration.

When the two objects are attracted, the speed with which they are moving toward each other depends on the strength of the pull force. This pull force is the gravitational pull.

Thus, the speed at which the objects were attracted to each other determined by the gravitational pull.

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2 years ago
URGENT: Two horizontal forces act on an object on a surface. There is a 20 Newton applied force to the left and a sliding fricti
anygoal [31]

Answer:

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Explanation:

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7 0
3 years ago
Particle moves in a circle of radius 90m with a constant speed 25m/s. how many revolution does it make in 30sec​
Serggg [28]

Answer:

<em>n =1.33 revolutions</em>

Explanation:

<u>Uniform Circular Motion</u>

The angular speed can be calculated in two different ways:

\displaystyle \omega=\frac{v}{r}

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\omega=2\pi f

Where:

f = frequency

Solving for f:

\displaystyle f=\frac{\omega}{2\pi}

Since the frequency is calculated when the number of revolutions n and the time t are known:

\displaystyle f=\frac{n}{t}

We can solve for n:

n=f.t

The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:

\displaystyle \omega=\frac{25}{90}

\displaystyle \omega=0.278\ rad/s

Now we calculate f:

\displaystyle f=\frac{0.278}{2\pi}

f=0.04421\ Hz

Calculating the number of revolutions:

n = 0.04421*30

n =1.33 revolutions

8 0
3 years ago
A satellite of mass 4500 kg orbits the Earth in a circular orbit of radius of 7.2 × 106 m (this is above the Earth's atmosphere)
pantera1 [17]

Answer:

7.457 * 10³ m/s

Explanation:

Parameters given:

Mass of earth, M = 6 * 10^24 kg

Radius of orbit, R = 7.2 * 10^6 m

Orbital velocity is given as:

v = √(GM/R)

Where G = gravitational constant

v = √(6.673 * 10^(-11) * 6 * 10^24)/(7.2 * 10^6)

v = √(5.561 * 10^7)

v = 7.457 * 10³ m/s

4 0
3 years ago
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