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meriva
3 years ago
14

A circular metal loop is kept entirely within a magnetic field, but moved to a region of higher field strength while not rotated

. What could you do to its diameter to prevent an induced current in it? Explain.
Physics
1 answer:
Advocard [28]3 years ago
8 0

The Answer:

The diameter will be reduced or shorten to prevent the induced current in the metal loop

explanation:

Magnetic flux is given as

Φ = BA•Cosθ

Since the angle is kept constant.

So to have same magnetic flux with larger magnetic field required only the diameter to changed

From the equation above,

Φ = BA•Cosθ

B= Φ / A•Cosθ

Since both Flux and the angle is constant

Then, The magnetic field is inversely proportional to the Area

And the areas is a function of diameter, Area = πd²/4

So to have a larger magnetic field, we need to reduce or shorten the diameter.

As d reduces, B increases.

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The deceleration of the car is observed as 2 m/s^2.

<h3>What is deceleration?</h3>

The term deceleration has to do with the decrease of velocity with time.

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7 0
2 years ago
Which of the angles shown in this picture is the angle of incidence?<br> A<br> B
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The pictures are not attached, therefore, I cannot give a specific choice.
However, I will try to help you out.

The angle of incidence is defined as the angle formed between the ray of light and the normal to the surface that the ray is falling on.

The angle of incidence can be shown in the attached image.

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6 0
3 years ago
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4 years ago
To win the game, a place kicker must kick a
masya89 [10]

Answer:

0.57 m

Explanation:

First of all, we need to calculate the time it takes for the ball to cover the horizontal distance between the starting position and the crossbar. This can be done by analzying the horizontal motion only. In fact, the horizontal velocity is constant and it is

v_x = u cos \theta = (15)(cos 51.7^{\circ})=9.30 m/s

And the distance to cover is

d = 19 m

So the time taken is

t=\frac{d}{v_x}=\frac{19}{9.30}=2.04 s

Now we want to find how high the ball is at that time. The initial vertical velocity is

u_y = u sin \theta = (15)(sin 51.7^{\circ})=11.77 m/s

So the vertical position of the ball at time t is

y(t) = u_y t - \frac{1}{2}gt^2

where g = 9.8 m/s^2 is the acceleration of gravity. Substituting t = 2.04 s, we find

y=(11.77)(2.04)-\frac{1}{2}(9.8)(2.04)^2=3.62 m

The crossbar height is 3.05 m, so the difference is

\Delta h = 3.62 - 3.05 =0.57 m

So the ball passes 0.57 m above the crossbar.

8 0
3 years ago
In what way could a random mutation provide an organism with<br> an advantage?
andreyandreev [35.5K]

Answer:

They are called beneficial mutations. They lead to new versions of proteins that help organisms adapt to changes in their environment. Beneficial mutations are essential for evolution to occur. They increase an organism's changes of surviving or reproducing, so they are likely to become more common over time.

Explanation:

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