Answer:
Therefore, the revolutions that each tire makes is:

Explanation:
We can use the following equation:
(1)
The angular acceleration is:



and the initial angular velocity is:



Now, using equation (1) we can find the revolutions of the tire.

Therefore, the revolutions that each tire makes is:

I hope it helps you!
Elastic potential energy.
When you stretch a rubber band it has the "potential" to do work, to fly in a given direction. In doing so it changes it's elastic potential energy to kinetic energy.
Answer:
Explanation:
Given
Volume of fixed chamber 
Initial Temperature 
Final Temperature 
Heat Supplied 
From First law of thermodynamics
Change in internal energy of the system is equal to heat added minus work done by the system

as the volume is fixed therefore work

thus 
for mono-atomic gas is 

and 1 mole contains 
thus No of molecules
No of molecules