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3 years ago

6

The circuit below shows some of the circuity in a small toy robot. When the circuit is on, the robot moves its arms (the motor)

and blinks a light on its head (the light bulb).
A. How much current is in the circuit when these things are happening? Hint: To find the total resistance of the circuit, add the two resistances together.

1 answer:

djyliett [7]3 years ago

6 0

Answer:

dear can you provide the circuit of the robot

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Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of

STatiana [176]

Answer:

$2.27\cdot 10^{49}$

Explanation:

The gravitational force between the proton and the electron is given by

$F_G=G\frac{m_p m_e}{r^2}$

where

G is the gravitational constant

$m_p$ is the proton mass

$m_e$ is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N$

The electrical force between the proton and the electron is given by

$F_E=k\frac{q_p q_e}{r^2}$

where

k is the Coulomb constant

$q_p = q_e = q$ is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N$

So, the ratio of the electrical force to the gravitational force is

$\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}$

So, we see that the electrical force is much larger than the gravitational force.

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A(n) _______ studies physical components and characteristics of celestial objects.

inna [77]

Answer:

Astronomers?

Explanation:

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2 years ago

a peice of titanium metal has a mass of 67.5 gm and a volume of 15 cm cubed. what is the density od titanium?

Nuetrik [128]

density=mass/volume

mass=67.5

volume=15cm cube

so

67.5/15

4.5g/cm cube

6 0

3 years ago

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ddd [48]

Answer:211.11 gm

Explanation:

Given

mass of lighter block $m_1=100 gm$

mass of heavier block is $m_2$

acceleration of system $a=3.5 m/s^2$

From diagram

for lighter block

$T-m_1g=m_1a$

$T=m_1(g+a)$

For heavier Block

$m_2g-T=m_2a$

$T=m_2(g-a)$

Equating Tension T

$m_1(g+a)=m_2(g-a)$

$m_2=m_1\cdot \frac{g+a}{g-a}$

$m_2=m_1\cdot \frac{9.8+3.5}{9.8-3.5}$

$m_2=0.1\cdot 2.11$

$m_2=0.2111 kg$

$m_2=211.11 gm$

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Calculate the electric field at the location of a charge if the electric force is 10 newtons and the charge on the particle is 6

kolezko [41]

I think it may be c, 1.7 v. I work with electricity a lot.

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