The circuit below shows some of the circuity in a small toy robot. When the circuit is on, the robot moves its arms (the motor)
1 answer:
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It’s solved by using a pretty standard formula for efficiency.
Answer:
has units of distance
has units of distance over time
has units of distance over
has units of distance over
Explanation:
Since the expression for the distance is:
then:
has units of distance
has units of distance over time
has units of distance over
has units of distance over
because we are supposed to be able to add all of the terms and get a distance. So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.