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kirill115 [55]
3 years ago
6

The circuit below shows some of the circuity in a small toy robot. When the circuit is on, the robot moves its arms (the motor)

and blinks a light on its head (the light bulb).
A. How much current is in the circuit when these things are happening? Hint: To find the total resistance of the circuit, add the two resistances together.
Physics
1 answer:
djyliett [7]3 years ago
6 0

Answer:

dear can you provide the circuit of the robot

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When magnesium fluoride reacts with iodine, the products are fluorine and magnesium iodide. What would the equation be?
likoan [24]

Answer:

Explanation:

Every chemical reaction can be represented by simple chemical equations that shows how compounds are combining to give some products.

Such reactions are usually made up of:

     Reactants on the left hand side

     Products on the right hand side

            Reactants  →  Products

In this given problem;

            Reactants are :   Magnesium fluoride  = MgF₂

                                             Iodine in form of Iodide   = I₂

           Product : Magnesium iodide  = MgI₂

             

               MgF₂   +     I₂    →       MgI₂   +   F₂

   

                             

   

7 0
3 years ago
A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m​
Mars2501 [29]

Answer:

formula used K=F/∆l

∆l is the elongation of the spring

  1. F=10N
  2. ∆l=20mm===> 0.02m
  3. K=10N divided 0.02m= 500N/m
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Tightness of the sciatic nerve can result in lower back pain true or false
uysha [10]
The answer is false. 
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3 years ago
A large plate carries a uniform charge density σ = 8. 85 × 10-9 c/m2. a pattern showing equipotential surfaces with a 5 v potent
vfiekz [6]

The potential difference comes out to be

10 \times 10 {}^{ - 3} m

Given:

σ = 8. 85 × 10-9 c/m2

we know,

E = \frac{σ}{2ε0}

E =  \frac{8.85 \times 10 {}^{ - 9} }{2ε0}

E =  \frac{v}{d}

given the potential difference between two equipotential surface=5v

E=∆v

∆d=∆v/E

=  \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} }

Δ = 10 \times 10 {}^{ - 3} m

Thus the potential difference is

10 \times 10 {}^{ - 3} m

Learn more about potential difference from here: brainly.com/question/28165869

#SPJ4

5 0
1 year ago
Two objects of masses m1 and m2, with m1 < m2, have equal kinetic energy. How do the magnitudes of their momenta compare
slavikrds [6]

Answer:

every name on here is physics whyyyy but anyways happy news yr eve

Explanation:

6 0
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