The empirical formula : C₁₂H₁₇N₂O₄P
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Further explanation
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The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components
The principle of determining empirical formula
- Determine the mass ratio of the constituent elements of the compound.
- Determine the mole ratio by by dividing the percentage by the atomic mass
![\tt \dfrac{50.7}{12}=4.225](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B50.7%7D%7B12%7D%3D4.225)
![\tt \dfrac{6.03}{1}=6.03](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B6.03%7D%7B1%7D%3D6.03)
![\tt \dfrac{9.86}{14}=0.704](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B9.86%7D%7B14%7D%3D0.704)
![\tt \dfrac{22.51}{16}=1.407](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B22.51%7D%7B16%7D%3D1.407)
![\tt \dfrac{10.9}{31}=0.352](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B10.9%7D%7B31%7D%3D0.352)
Divide by the smallest mole ratio(0.352)
C : H : N : O : P
![\tt C\rightarrow \dfrac{4.225}{0.352}=12](https://tex.z-dn.net/?f=%5Ctt%20C%5Crightarrow%20%5Cdfrac%7B4.225%7D%7B0.352%7D%3D12)
![\tt H\rightarrow \dfrac{6.03}{0.352}=17](https://tex.z-dn.net/?f=%5Ctt%20H%5Crightarrow%20%5Cdfrac%7B6.03%7D%7B0.352%7D%3D17)
![\tt N\rightarrow \dfrac{0.704}{0.352}=2](https://tex.z-dn.net/?f=%5Ctt%20N%5Crightarrow%20%5Cdfrac%7B0.704%7D%7B0.352%7D%3D2)
![\tt O\rightarrow \dfrac{1.407}{0.352}=4](https://tex.z-dn.net/?f=%5Ctt%20O%5Crightarrow%20%5Cdfrac%7B1.407%7D%7B0.352%7D%3D4)
![\tt P\rightarrow \dfrac{0.352}{0.352}=1](https://tex.z-dn.net/?f=%5Ctt%20P%5Crightarrow%20%5Cdfrac%7B0.352%7D%7B0.352%7D%3D1)
Answer:
Option a
Explanation:
Ester ethyl butanoate is a Chemical compound with Molar mass of 116.16 g/mol, the Boiling point is 121 °C and the Density is 879 kg/m³.
Looking at the chemical representation of the compound, it can be shown that the chemical compound contains the an ester functional group and this it is formed through the reaction of a -COOH containing compound/salt and an alcohol.
The chemical representations showing the chemical reaction is given below;
CH3CH2CH2COOCH2CH3 + Acid(H2O, H^+) =========> C2H5OH + C4H8O2.
Thus, acidic hydrolysis of the ester gives ethyl alcohol and butanoic acid.
Answer:
Look Below
Explanation:
Capillary action is adhesion of water. In plants, capillary action allows water to move from the roots to leaves. In animals, capillary action plays a role in respiration where oxygen-poor blood oxygenates in the capillaries.
Here are the solutions
1. Double replacement
2. Combustion
3. Single replacement
4. Synthesis
5. Decomposition.
2 C4H10 + 13 O2 → 8 CO2 + 10H2O
Given, Heat of formation of C4H10 = = -125.7 kJ/molHeat of formation of water = = -241.82 kJ/molHeat of formation of CO2 = = -393.5 kJ/mol
Thus, enthalpy of combustion = ΔH = ∑Hproducts - ∑Hreactants = 8 + 10 - 2 = (-393.5X8) + (-241.82X10) - (-125.7X2) = -5314.8 kJ/mol
This energy would result in combustion of 2 moles of butane∴ For 1 mole, energy required for combustion of butane = -5314.8/2 = -2657.4 kJ/mol