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lubasha [3.4K]
4 years ago
8

Butane C4 H10 (g),(mc016-1.jpgHf = –125.7), combusts in the presence of oxygen to form CO2 (g) (mc016-2.jpgHf = –393.5 kJ/mol),

and H2 O(g) (mc016-3.jpgHf = –241.82) in the reaction:
Chemistry
1 answer:
jenyasd209 [6]4 years ago
6 0
2 C4H10   +      13 O2       →      8 CO2   +     10H2O
Given, Heat of formation of C4H10 =  = -125.7 kJ/molHeat of formation of water =  = -241.82 kJ/molHeat of formation of CO2 =  = -393.5 kJ/mol
Thus, enthalpy of combustion = ΔH = ∑Hproducts - ∑Hreactants                                               = 8 + 10 - 2                                                = (-393.5X8) + (-241.82X10) - (-125.7X2)                                               = -5314.8 kJ/mol
This energy would result in combustion of 2 moles of butane∴ For 1 mole, energy required for combustion of butane = -5314.8/2 = -2657.4 kJ/mol
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AleksandrR [38]

Answer:

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

Explanation:

The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:

SiO_2+3C\rightarrow SiC+2CO

1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.

Mass of SiC = 3.00kg = 3000.00 g

1 kg = 1000 g

Molecular mass of SiC = 40 g/mol

Moles of SiC = \frac{3000.00 g}{40 g/mol}= 75 mol

According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.

Then 75 moles of SiC will be produce from:

\frac{1}{1}\times 75 mol=75 mol of silicon dioxide.

mass of 75 moles of silicon dioxde:

75 mol\times 60 g/mol=4500 g=4.5 kg

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

3 0
4 years ago
The frequency of an x-ray wave is 3.0 x 1012 MHz. Its wave speed is 3.0x 108 m/s. Calculate the wavelength of the x-ray wave bel
elena55 [62]

Answer:

λ = 1*10⁻¹⁰m

Explanation:

Frequency (f) = 3.0*10¹²MHz = 3.0*10¹⁸Hz

Speed (v) = 3.0*10⁸m/s

Speed (v) of a wave = frequency (f) * wavelength (λ)

V = fλ

Solve for λ,

λ = v / f

λ = 3.0*10⁸ / 3.0*10¹⁸

λ = 1*10⁻¹⁰m

λ = 0.

6 0
3 years ago
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Answer:

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Explanation:

Because, inside from garden with big tub like a stock tank on your patio. They grow tubers planted in pots beneath the water and send up stems with rounded leaves and star-shaped blossoms that float on the surface.

I hope it helps to us. Always welcome my youngest sister:). keep learning and God bless.

6 0
2 years ago
A solution of ammonia and water contains 4.20×1025 water molecules and 6.20×1024 ammonia molecules. how many total hydrogen atom
Setler79 [48]

The molecular formula of water and ammonia is H_2O and NH_3 respectively.

From the atomic symbol of water it is clear that 1 mole of water contains 2 moles of hydrogen.

So, 4.20\times 10^{25} molecules of water contains 2\times 4.20\times 10^{25} = 8.40\times 10^{25} atoms of hydrogen.

From the atomic symbol of ammonia it is clear that 1 mole of ammonia contains 3 moles of hydrogen.

So, 6.20\times 10^{24} molecules of ammonia contains 3\times 6.20\times 10^{24} = 18.6\times 10^{24} atoms of hydrogen.

Total number of hydrogen atoms present in the solution = number of hydrogen atoms in water + number of hydrogen atoms in ammonia.

Substituting the values,

Total number of hydrogen atoms present in the solution = 8.40\times 10^{25}+1.86\times 10^{25}

Total number of hydrogen atoms present in the solution = 10.26\times 10^{25} atoms.

Hence, the total number of hydrogen atoms present in the solution is 10.26\times 10^{25} atoms.

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