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aleksklad [387]
3 years ago
11

What is capillary action? Describe how capillary action shown by water is useful for plants and animals on Earth.

Chemistry
2 answers:
EastWind [94]3 years ago
7 0

Answer: The capillary action of water can be defined as the property of water by which it travels through the tube in upward direction which is opposite the gravity.

Explanation: This property of water is due to adhesion, cohesion and surface tension of water which allows it to climb through the tube. This property allows the plants to uptake water from the soil.

The water also moves against the gravity in the body of plants and animals with the help of capillary action.

Shtirlitz [24]3 years ago
4 0

Answer:

Look Below

Explanation:

Capillary action is adhesion of water. In plants, capillary action allows water to move from the roots to leaves. In animals, capillary action plays a role in respiration where oxygen-poor blood oxygenates in the capillaries.

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Balance the following equation:
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Answer: a) 2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

b) 1 mole of SO_2 is produced.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The skeletal equation is:

K_2CrO_4+Na_2SO_3+HCl\rightarrow KCl+Na_2SO_4+CrCl_3 +H_2O

The balanced equation will be:

2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

Thus the coefficients are 2, 3 , 10 , 4 , 3 , 2 and 5.

b) Oxidation: 2I-^-\rightarrow I_2+2e-^-

Reduction: SO_4^{2-}+2e^-+4H^+\rightarrow SO_2+2H_2O

Net reaction:  2I-^-+SO_4^{2-}+4H^+\rightarrow I_2+SO_2+2H_2O

When 1 mole of I_2 is produced, 1 mole of SO_2 is produced.

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3 years ago
An amphoteric salt is one that contains an anion that can act as either an acid or a base in water. Baking soda, NaHCO3, is an e
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pH = 8.34

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H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>

<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>

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pKa1 = 6.37; pKa2 = 10.32

As the pH of amphoteric salts is:

pH = (pKa1 + pKa2) / 2

<h2>pH = 8.34</h2>
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