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3 years ago

What is capillary action? Describe how capillary action shown by water is useful for plants and animals on Earth.

2 answers:

7 0

Answer: The capillary action of water can be defined as the property of water by which it travels through the tube in upward direction which is opposite the gravity.

Explanation: This property of water is due to adhesion, cohesion and surface tension of water which allows it to climb through the tube. This property allows the plants to uptake water from the soil.

The water also moves against the gravity in the body of plants and animals with the help of capillary action.

Shtirlitz [24]3 years ago

4 0

Answer:

Look Below

Explanation:

Capillary action is adhesion of water. In plants, capillary action allows water to move from the roots to leaves. In animals, capillary action plays a role in respiration where oxygen-poor blood oxygenates in the capillaries.

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Hydrogen bonds form between neighboring water molecules because of ________. A. electron transfer B. electron sharing C. the vis

Oduvanchick [21]

Answer:

Answer is B.

Explanation:

Hydrogen bonds forms when hydrogen atom is attracted towards oxygen atom of other water. A proton is shared by two ion electrons pair in which oxygen atom is partially negatively charged while hydrogen atom is partially positively charged.

7 0

2 years ago

Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s

Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

$N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}$

where N is amount of radioactive nuclide after t time, $N_{0}$ is initial amount of radioactive nuclide and $t_{\frac{1}{2}}$ is half life of radioactive nuclide

Here $N_{0}=4.60 mg$ , $t=4.1\times 10^{9}yr$ and $t_{\frac{1}{2}}=4.5\times 10^{9}yr$

So, $N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}$

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0

3 years ago

What’s the relationship between atomic radius and ease of oxidation on the activity series.

user100 [1]

The bigger the atomic radius the easier it is to oxidise the atom. Remember that an atom is oxidized by the loss of an electron.

Explanation:

The bigger the atomic radius the further away the valence electron are from the attractive force of the atomic nucleus. This means that the energy required to remove an electron from the valence shell is easier compared to an atom with a smaller atomic radius. This is because you need to overcome the attractive force of the nucleus on the electron for you to oxidize the atom.

Learn More:

For more on oxidation energy check out;

brainly.com/question/8835627

brainly.com/question/13507502

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3 0

3 years ago

Please help 21 points

Novosadov [1.4K]

Answer:

You

Explanation: