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3 years ago

What characteristic of a solid is most responsible for their structure

Chemistry

1 answer:

amm18123 years ago

4 0

1. BONDING PATTERNS BETWEEN ATOMS.

2. TYPES OF MATTER IN SOLIDS.

Solids generally have their constituent particles arranged in a pattern known as crystalline structure. The crystalline structure of the solid is due to the types of matter and the chemical bonds that exist between the particles of solids. The constituent particles of a solid can be atoms, ions or molecules.

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An astronomer observes an asteroid in the solar system. He notes that the asteroid is three times farther from the Sun than Eart

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Answer:

3 AU

Explanation:

The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.

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3 years ago

Radiation is a measure of average kinetic energy of particles in an object true or false

laila [671]

Answer:false

Explanation:

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3 years ago

How many moles of hydrogen are required to react with 4.6 x 10 22 molecules of nitrogen?

V125BC [204]

Answer: 6 moles

Take a look at the balanced chemical equation for this synthesis reaction

N 2(g] + 3 H 2(g] → 2 NH 3(g]

Notice that you have a 1:3 mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have 2 moles of nitrogen taking part in the reaction, you will need

2 moles N 2 ⋅ 3 moles H 2 /1 mole N 2 = 6 moles H 2

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3 years ago

Arizona was the site of a 400,000-acre wildfire in June 2002. How much carbon dioxide (CO2) was produced into the atmosphere by

kodGreya [7K]

Answer:

2.97 × 10¹³ g

Explanation:

First, we have to calculate the biomass the is burned. We can establish the following relations:

2.47 acre = 10,000 m²
10 kg of C occupy an area of 1 m²
50% of the biomass is burned

The biomass burned in the site of 400,000 acre is:

$400,000acre\times\frac{10,000m^{2} }{2.47acre} \times \frac{10kgC}{m^{2} } \times 50\% = 8.10 \times 10^{9} kgC$

Let's consider the combustion of carbon.

C(s) + O₂(g) ⇒ CO₂(g)

We can establish the following relations:

The molar mass of C is 12.01 g/mol
1 mole of C produces 1 mole of CO₂
The molar mass of CO₂ is 44.01 g/mol

The mass of produced is CO₂:

$8.10 \times 10^{12}gC \times \frac{1molC}{12.01gC} \times \frac{1molCO_{2}}{1molC} \times \frac{44.01gCO_{2}}{1molCO_{2}} =2.97 \times 10^{13} gCO_{2}$

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3 years ago

( urgent help needed!! 50pts + brainliest )

Ivanshal [37]

Answer:

Thorium-234 option a .......

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3 years ago

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