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3 years ago

What characteristic of a solid is most responsible for their structure

Chemistry

1 answer:

amm18123 years ago

4 0

1. BONDING PATTERNS BETWEEN ATOMS.

2. TYPES OF MATTER IN SOLIDS.

Solids generally have their constituent particles arranged in a pattern known as crystalline structure. The crystalline structure of the solid is due to the types of matter and the chemical bonds that exist between the particles of solids. The constituent particles of a solid can be atoms, ions or molecules.

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What mass of HBO2 is produced from the<br> combustion of 139.5 g of B2H6?<br> Answer in units of g.

aliina [53]

Answer:

$m_{HBO_2}=441.8gHBO_2$

Explanation:

Hello there!

In this case, since the combustion of B2H6 is:

$B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O$

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:

$m_{HBO_2}=139.5gB_2H_6*\frac{1molB_2H_6}{27.67gB_2H_6} *\frac{2molHBO_2}{1molB_2H_6} *\frac{43.82gHBO_2}{1molHBO_2}$

$m_{HBO_2}=441.8gHBO_2$

Best regards!

5 0

2 years ago

CO 2 is an element. true or false

iren [92.7K]

Answer: false

Explanation:

f this helps typically an element wont have a 2 next to it, to see if something is an element or compound check for the element on the periodic table and see if the structure or name matches the one given to you on the question. for example here it is Co2 on the periodic table it's simply written as Co

co2 or carbon dioxide is a compound not an element, you can even check this on the periodic table

7 0

2 years ago

Read 2 more answers

How many grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline?

egoroff_w [7]

Grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline is 45.5g

Octane is a hydrocarbon which burns in gasoline in presence of oxygen according to the given balanced chemical equation,

2C₈H₁₈ + 25O₂------> 16CO₂ + 18H₂0

Molar mass of octane = 114.23g/mol

Molar mass of Oxygen = 32g/mol

According to the stiochiometry of the balanced equation the mole ratio of Octane and Oxygen is 2:25

2 mole of octane needs 25 mole of oxygen

1 mole of octane needs 12.5 moleof oxygen

114.23g of octane needs 400g of oxygen

13g of octane needs 45.5g of oxygen

Mass of oxygen needed =45.5g

Hence, the Mass of oxygen needed is 45.5g for the combustion of octane in gasoline.

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

5 0

1 year ago

Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 V Cu2++2e−→Cu;E∘=0

Maru [420]

Answer:

Explanation:

To calculate the cell potential we use the relation:

Eº cell = Eº oxidation + Eº reduction

Now in order to determine which of the species is going to be oxidized, we have to remember that the more the value of the reduction potential is negative, the greater its tendency to be oxidized is. In electrochemistry we use the values of the reductions potential in the tables for simplicity because the only thing we need to do is change the sign of the reduction potential for the oxized species .

So the species that is going to be oxidized is the Aluminium, and therefore:

Eº cell = -( -1.66 V ) + 0.340 V = 5.06 V

Equally valid is to write the equation as:

Eº cell = Eº reduction for the reduced species - Eº reduction for the oxidized species

These two expressions are equivalent, choose the one you fell more comfortable but be careful with the signs.

3 0

2 years ago

Calculate the number of moles in 456 grams of lead, Pb

Kamila [148]

Mass 456
relative mass 82
moles
mass = rm x moles
456/82 = 5.5609756....

8 0

2 years ago