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sweet-ann [11.9K]
4 years ago
9

Please help me with chem!

Chemistry
1 answer:
Scilla [17]4 years ago
7 0

Answer:

96.0 grams of oxygen gas (O2) will be produced.

Option B is correct.

Explanation:

Step 1: Data given

Number of moles SO2 = 2.0 moles

Molar mass O2 = 32.0 g/mol

Step 2: The balanced equation

2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O(g)

Step 3: Calculate moles oxygen gas (O2)

For 2 moles H2S we need 3 moles O2 to produce 2 moles SO2 and 2 moles H2O

For 2.0 moles SO2 produced we need 3/2 * 2.0 = 3.0 moles O2

Step 4: Calculate mass O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 3.0 moles * 32.0 g/mol

Mass O2 = 96.0 grams

96.0 grams of oxygen gas (O2) will be produced.

Option B is correct.

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Answer:

Explanation:

01: 5.3316+6.87+37.48

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5 0
3 years ago
What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
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Answer:

T_f for given question is 2.79 and T_b is 0.52

\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

\Delta T_b = I \times K_b \times (w/M)/ x

\Delta T_b = I \times K_b \times w/Mx

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