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Kazeer [188]
3 years ago
5

I haven’t had a teacher for my chemistry class and in order for me to pass I need to pass this here final. Can someone please he

lp me??

Chemistry
1 answer:
QveST [7]3 years ago
5 0
The answer is G Container 2 
.
Hope this helps
.
Zane 
.
<span> esskeetit</span>
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Which of the following is used to show sound waves?
Ipatiy [6.2K]
I think it’s c bc it makes more sense
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3 years ago
The removal of one or more electrons from a neutral atom results in and
Studentka2010 [4]

Answer:

The removal of one or more electrons from a neutral atom results in a cation.

Explanation:

When you remove electrons from a neutral atom, the atom becomes more positive. Electrons have a negative charge and the protons inside of the nucleus have a positive charge. When electrons are removed, the positive charges from the protons outweigh the negative charges. This results in a positively charged atom, called a cation.

6 0
2 years ago
Alchemists in the Middle Ages dreamed of converting base metals, such as lead, into precious metals—gold and silver. Why could t
lesantik [10]

Explanation:

Each element in the periodic table has different but fixed number of the protons in nucleus of it's atom, which is known as the atomic number.

Transmutation of one chemical element into the another involves the changing of the atomic number. Such nuclear reaction requires millions of the times more energy as compared to normal chemical reactions. Thus, the dream of  the alchemist of transmuting the lead into the gold was never achievable chemically .

Conversion of lead to gold in today's world:

This conversion is indeed possible. The requirements are a particle accelerator, tremendous supply of the energy. Nuclear scientists at the Lawrence Berkeley National Laboratory located in California, more than 30 years ago, succeeded in producing very minute amounts of the gold from the bismuth. Bismuth is a metallic element which is adjacent to the lead on periodic table. Same process would work for the lead but isolating gold at end of reaction would prove much more difficult because lead is available in many isotopes. The homogeneous nature of the element means that it is easier to separate the gold from the bismuth as compared to separate the gold from the lead which has four  isotopic identities which all are stable.

4 0
3 years ago
A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 ml of water. an acid-base indicator is added and the
Fofino [41]

Answer:

(a) 102.6g/mol

(b) Rubidium

Explanation:

Hello,

This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

V_{base}=0.1L; M_{acid}=2.5M, V_{acid}=0.017L\\V_{base}M_{base}=V_{acid}M_{acid}

Solving for the molarity of base we've got:

M_{base}=\frac{M_{acid}*V_{acid}}{V_{base}}=\frac{2.50M*0.017L}{0.1L} =0.425M=0.425mol/L

Now, we can compute the moles of the base as:

n_{base}=0.425mol/L*0.1L=0.0425mol

(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:

\frac{4.36g}{0.0425mol} =102.6g/mol

(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:

102.6g/mol-16g/mol-1g/mol=85.6g/mol

So, that atomic mass dovetails to the Rubidium's atomic mass.

Best regards.

8 0
3 years ago
He isotope 62(over28ni has the largest binding energy per nucleon of any isotope. calculate this value from the atomic mass of n
irina [24]
The atomic mass of the isotope Ni ( 62 over 28 ) = 61.928345 amu.
Mass of the electrons: 28 · 5.4584 · 10^(-4 ) amu = 0.0152838 amu ( g/mol )
Mass of the nuclei:
61.928345 amu - 0.0152838 amu = 61.913062 amu (g/mol)
The mass difference between a nucleus and its constituent nucleons is called the mass defect.
For Ni ( 62 over 28 ): Mass of the protons: 28 · 1.00728 amu = 28.20384 amu
Mass of the neutrons: 34 · 1.00866 amu = 34.299444 amu
In total : 62.49828 amu
The mass defect = 62.49828 - 61.913062 = 0.585218 amu
Nucleus binding energy:
E = Δm · c² ( the Einstein relationship )
E = 0.585218 · ( 2.9979 · 10^8 m/s )² · 1 / (6.022 · 10^23) · 1 kg / 1000 g =
= 0.585218 · 8.9874044 · 10 ^16 : (6.022 · 10^23) · 0.001 =
= ( 5.2595908 : 6.022 ) · 0.001 · 10^(-7 ) =
= 0.0008733 · 10^(-7) J = 8.733 · 10^(-11) J
The nucleus binding energy per nucleon:
8.733 · 10^(-11) J : 62 =  0.14085 · 10 ^(-11) =
= 1.4085 · 10^(-12) J per nucleon.
4 0
3 years ago
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