Answer:
50.4÷1.18= 42.7m/s as speed is equal to the distance over the time taken
Traits for larger animals with bigger horns will be selected.
B. Performing experiments
Answer:
Yes, the heat that flows into the system is used to change the internal energy of the gas and becomes work done by the piston.
Explanation:
First law of thermodynamics known as Law of Conservation of Energy, states that energy can neither be created nor destroyed; energy can only be transferred or changed from one form to another.
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system. In equation form, the first law of thermodynamics.
This is the first law of thermodynamics
ΔE= Q− W
ΔE= change internal energy of the system.
Q= heat transfer into the system
And
W= work done by the system.
Rewriting the equation
ΔE= Q− W
Q=ΔE +W
Show that the heat flowing l into the system is transferred to the internal energy of the system and the work done by the piston
So the third option is correct
Answer:
1) The balloon will shrink
2) The balloon will grow bigger and regain its shape
Explanation:
By the kinetic theory of gases, we have;
![v_{rms} = \sqrt{\dfrac{3 \cdot R \cdot T}{MW} }](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cdfrac%7B3%20%5Ccdot%20R%20%5Ccdot%20T%7D%7BMW%7D%20%7D)
![P = \dfrac{n \cdot MW \cdot vrms^2}{3 \cdot V}](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7Bn%20%5Ccdot%20MW%20%5Ccdot%20vrms%5E2%7D%7B3%20%5Ccdot%20V%7D)
Where;
= RMS Speed
R = The universal gas constant
T = The temperature
MW = The Molecular weight
n = The number of moles
V = The volume
P = The pressure
1) When the balloon is placed in the refrigerator for minutes, the temperature inside the balloon will drop and RMS speed will reduce, however due to the elastic wall of the balloon, the pressure will remain the same therefore the volume will reduce and the balloon will shrink
2) When the balloon is placed on the kitchen counter, the temperature inside the balloon will rise leading to the increase in the RMS speed which will raise the pressure effect on the wall of the balloon as the balloon is made of elastic material, as the pressure rises, the wall expands to keep the pressure constant and the volume occupied by the air particles will increase, the balloon will grow bigger and regain its shape.