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krok68 [10]
4 years ago
11

A sphere has an unknown amount of charge distributed uniformly at a distance of 0.56cm from the center of the of the sphere, the

electric feld point directly toward centre of the phone which has a magnitude of 1.6x10NC how much charge is on the sphere.​
Physics
1 answer:
Mars2501 [29]4 years ago
7 0
2+2+2+2+22++2+2+2+2+222+2++2c2+2+2+2+2+2
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Which form of energy is involved in weighting fruit on a spring scale ?
alexdok [17]
The correct answer is elastic potential energy.

I hoped this helped!
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Which task would a colorectal surgeon perform?
topjm [15]
Answer: 4. removing tumors in the large intestine
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3 years ago
The sun is 60° above the horizon. Rays from the sun strike the still surface of a pond and cast a shadow of a stick that is stuc
Kipish [7]

Answer:

shadow length 7.67 cm

Explanation:

given data:

refractive index of water is 1.33

by snell's law we have

n_{air} sin30 =n_{water} sin\theta

1*0.5 = 1.33*sin\theta

solving for\theta

sin\theta = \frac{3}{8}

\theta = sin^{-1}\frac{3}{8}

\theta =  22 degree

from shadow- stick traingle

tan(90-\theta) = cot\theta = \frac{h}{s}

s = \frac{h}{cot\theta} = h tan\theta

s = 19tan22 = 7.67 cm

s = shadow length

5 0
3 years ago
How far can a person run in 15 minutes if he or she runs at an average speed of 16 km/hr
Studentka2010 [4]
4 km/hr. There are four quarters in an hour, so just divide 16 by 4 and you get 4. It is directly proportional.
6 0
3 years ago
Two one-coulomb point charges are at a distance of 1.67 m from each other. What is the size of the electric force between the tw
pychu [463]

Explanation:

The given data is as follows.

       distance (r) = 1.67 m

     q_{1} = q_{2} = 1 C

It is known that formula for electric force between two charges is as follows.

          F = \frac{kq_{1} \times q_{2}}{r^{2}}

Hence, putting the given values into the above formula as follows.

       \frac{9 \times 10^{9} \times 1 \times 1}{(1.67)^{2}}

            = 3.227 \times 10^{9}

As it is given that mass of  Falcon Heavy rocket is 1421. Therefore, weight of 1 Falcon rocket is as follows.

       weight of 1 falcon rocket = 142 \times 10^{3} \times 9.8

Therefore, number of falcon rockets will be calculated as follows.

         No. of falcon rockets = \frac{3.227 \times 10^{9}}{142000 \times 9.8}

                              = 2.31897 \times 10^{3}

                              = 2318.9 falcons

Thus, we can conclude that force between the two point charges above is equal to the weight of 2318.9 Falcon Heavy rockets.

5 0
3 years ago
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