Answer: the correct answer is 7.8026035971 x 10^(-13) joule
Explanation:
Use Energy Conservation. By ``alpha decay converts'', we mean that the parent particle turns into an alpha particle and daughter particles. Adding the mass of the alpha and daughter radon, we get
m = 4.00260 u + 222.01757 u = 226.02017 u .
The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is
Delta m = 226.02540 u - 226.02017 u = 0.00523 u ,
which is equivalent to an energy change of
Delta E = (0.00523 u)*(931.5MeV/1u)
Delta E = 4.87 MeV
Converting 4.87 MeV to Joules
1 joule [J] = 6241506363094 mega-electrón voltio [MeV]
4 mega-electrón voltio = 6.40870932 x 10^(-13) joule
4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule
B. Reversing the current direction will cause the force deflecting the
wire to be perpendicular to the magnetic field but in the opposite
direction.
The radial force on the particle is given by the Lorentz force. They don't give you the velocity so you have to solve for it in terms of the radius and get them to cancel.
Answer:
![F=5.8\times 10^{8}\ N](https://tex.z-dn.net/?f=F%3D5.8%5Ctimes%2010%5E%7B8%7D%5C%20N)
![F=35.57\times 10^{21}\ N](https://tex.z-dn.net/?f=F%3D35.57%5Ctimes%2010%5E%7B21%7D%5C%20N)
Explanation:
Given that
Intensity I
![I= 1.39\ KW/m^2](https://tex.z-dn.net/?f=I%3D%201.39%5C%20KW%2Fm%5E2)
![Speed\ of \ light = 2.99\times 10^8\ m/s](https://tex.z-dn.net/?f=Speed%5C%20of%20%5C%20light%20%3D%202.99%5Ctimes%2010%5E8%5C%20m%2Fs)
Radius of earth,R = 6370 Km
We know that surface area of earth, A
![A=\pi R^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20R%5E2)
![A=\pi (6370\times 10^3)^2\ m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20%286370%5Ctimes%2010%5E3%29%5E2%5C%20m%5E2)
![A=1.27\times 10^{14}\ m^2](https://tex.z-dn.net/?f=A%3D1.27%5Ctimes%2010%5E%7B14%7D%5C%20m%5E2)
As we know that pressure due to intensity given as
![P=\dfrac{I}{V}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BI%7D%7BV%7D)
V =Velocity of light
![V=3\times 10^8\ m/s](https://tex.z-dn.net/?f=V%3D3%5Ctimes%2010%5E8%5C%20m%2Fs)
![P=\dfrac{1.39\times 1000}{=3\times 10^8}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B1.39%5Ctimes%201000%7D%7B%3D3%5Ctimes%2010%5E8%7D)
![P=4.6\times 10^{-6}\ Pa](https://tex.z-dn.net/?f=P%3D4.6%5Ctimes%2010%5E%7B-6%7D%5C%20Pa)
We know that force F
F = P .A
![F=4.6\times 10^{-6}\times 1.27\times 10^{14}\ N](https://tex.z-dn.net/?f=F%3D4.6%5Ctimes%2010%5E%7B-6%7D%5Ctimes%201.27%5Ctimes%2010%5E%7B14%7D%5C%20N)
![F=5.8\times 10^{8}\ N](https://tex.z-dn.net/?f=F%3D5.8%5Ctimes%2010%5E%7B8%7D%5C%20N)
b)Gravitational force F
![F=G\dfrac{m.M}{r^2}](https://tex.z-dn.net/?f=F%3DG%5Cdfrac%7Bm.M%7D%7Br%5E2%7D)
![M = mass\ of\ sun = 2\times 10^{30} kg\\m = mass\ of\ earth = 6\times 10^{24}kg](https://tex.z-dn.net/?f=M%20%3D%20mass%5C%20of%5C%20sun%20%3D%202%5Ctimes%2010%5E%7B30%7D%20kg%5C%5Cm%20%3D%20mass%5C%20of%5C%20earth%20%3D%206%5Ctimes%2010%5E%7B24%7Dkg)
![r =1.5\times 10^{11}\ m](https://tex.z-dn.net/?f=r%20%3D1.5%5Ctimes%2010%5E%7B11%7D%5C%20m)
![G =6.67\times 10^{-11}Nm^2/kg^2](https://tex.z-dn.net/?f=G%20%3D6.67%5Ctimes%2010%5E%7B-11%7DNm%5E2%2Fkg%5E2)
So F
![F=6.67\times 10^{-11}\times \dfrac{2\times 10^{30}\times 6\times 10^{24}kg}{1.5\times 10^{11}}](https://tex.z-dn.net/?f=F%3D6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%20%5Cdfrac%7B2%5Ctimes%2010%5E%7B30%7D%5Ctimes%206%5Ctimes%2010%5E%7B24%7Dkg%7D%7B1.5%5Ctimes%2010%5E%7B11%7D%7D)
![F=35.57\times 10^{21}\ N](https://tex.z-dn.net/?f=F%3D35.57%5Ctimes%2010%5E%7B21%7D%5C%20N)
PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG. PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG.