Answer:
Please see below as the answers are self-explanatory
Explanation:
a)
- A electric field line is an imaginary line, which has the property that the electric field vector is tangent to it at any point. It starts from positive charges (since the electric field by convention it has the direction of the trajectory that would take a positive test charge, so it always goes away from positive charges) and ends in negative charges.
b)
- Since the potential difference between two points represents the work per unit charge needed for a charge to move between these points, a equipotential surface is the one over which it is not needed to do work to move a charge from any point on the surface to any other point, which means that all points are at the same potential.
c)
- Equipotential surfaces are not necessarily physical surfaces, they can be defined in vaccum for instance.
- As an example, any spherical surface concentric with a point charge, is an equipotential surface, and it can be a real surface or a fictitious one.
Social groups<span> that we as </span>individuals<span> belong to, we have a </span>status<span> and a </span>role<span> to fulfill.</span>Status<span> is our relative social position within a </span>group<span>, while a </span>role<span> is ... Because of this </span>status<span>, he is expected to fulfill a </span>role<span> for his children ... These make it a crime to hire and promote people because they are </span>your<span> relatives.
put me as a brainiest </span><span />
Answer:
s = 90 m
a = 56 m/s²
Explanation:
I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t
Position is the integral of differential velocities
s = 
s = 3t³ + t² | from 0 to 3
s = 3(3)³ + 3² - (0) = 90 m
acceleration is the derivative of velocity
a = v' = 18t + 2
a(3) = 18(3) + 2 = 56 m/s²
You really can't tell.
Power = I^2 × R = V^2 / R ( unit in Watt)
For P = I^2 × R
Where we have P directly proportional to R, increase in Power leads to increase in R
So if we have 100 will have higher resistance
For P = V^2/R
Power is inversely proportional to resistance.
So increase in Power leads to decrease in resistance.
60 watt will have a higher resistance.
