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Svetllana [295]
3 years ago
5

A gymnast jumps straight up, with her center of mass moving at 4.73 m/s as she leaves the ground. How high above this point is h

er center of mass at the following times? (Ignore the effects of air resistance, and assume the initial height of her center of mass is at y = 0.)
Physics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:

At any time <em>t</em>, her altitud will be given by the following law:

y=0 + 4.73\frac{m}{s}\cdot t - \frac{1}{2} g\cdot t^{2}

Explanation:

We can consider the gymnast as a point particle in the position of her center of mass. The law of movement will be:

y=0 + 4.73\frac{m}{s}\cdot t - \frac{1}{2} g\cdot t^{2}

where <em>g </em>is gravity's acceleration which we can take as g=9.8\frac{m}{s^{2} }. We add <em>0 </em> in the last member just to note that at t=0 the vertical position is 0. If we knew that she was moving at 4.73\frac{m}{s} at 1m, we would have needed to put <em>1m </em>in the place of <em>0</em>.

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kvasek [131]

Answer:

a) a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

b) k = \frac{9.8}{9.74}=1.006

Explanation:

Part a

For this case we can begin finding the period like this:

T= \frac{1}{w} =\frac{1}{617 rad/s}=0.00162 s

Then we know that the centripetal acceleration is given by:

a= \frac{v^2}{r}

And the velocity is given by:

v=\frac{2\pi r}{T}

If we replace this into the acceleration we got:

a = \frac{(\frac{2\pi r}{T})^2}{r}= \frac{4 \pi^2 r}{T^2}

And we can replace the values and we got:

a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

Part b

For this case we want to find a value of k such that:

a= k 9.8

Where a = 9.74, so then we can solve for k like this:

k = \frac{9.8}{9.74}=1.006

8 0
3 years ago
 How many centimeters are there in meter? b. 10 c. d 1000 e. 10000 100 2. A centimeter is equal to 1 inch b.½inch C 1/2.54 inch
astra-53 [7]

Answer:

a) There are 100 centimeters in 1 meter.

b) \texttt{A cm is equal to }\frac{1}{2.54}\texttt{ inch}

Explanation:

a) We have the conversion

         1 m = 100 cm

   So there are 100 centimeters in 1 meter.

b) 1 inch = 2.54 cm

    1cm=\frac{1}{2.54}inch

   \texttt{A cm is equal to }\frac{1}{2.54}\texttt{ inch}

8 0
3 years ago
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olga_2 [115]

The correct option to the question is Matter.

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Moreover, Matter can be described as,

Matter is anything that has occupies space (has mass and volume).

For more information visit:

brainly.com/question/13280491

8 0
3 years ago
How is distance related to force in this experiment to mass
Elden [556K]
When distance<span> is increased the amount of </span>force<span> needed will depend on the </span>mass<span> of the object. </span>
5 0
3 years ago
Suppose that on earth you can throw a ball vertically upward a distance of 1.20 m. Given that the acceleration of gravity on the
tatuchka [14]

Answer:

7.04 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement on Earth = 1.2 m

a = Acceleration due to gravity on Moon = 1.67 m/s²

a = Acceleration due to gravity Earth= 9.81 m/s²

Accelration going up is considered as negetive

Initial Velocity of the ball

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow -u^2=2\times -9.81\times 1.2-0^2\\\Rightarrow u=\sqrt{2\times 9.81\times 1.2}\\\Rightarrow u=4.85\ m/s

Assuming that the ball is thrown with the same velocity on the Moon, displacement of the ball is

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-4.85^2}{2\times -1.67}\\\Rightarrow s=7.04\ m

The displacement of the ball on the moon is 7.04 m

6 0
3 years ago
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