Answer:
(a). The speed at point B is 7.41 m/s.
(b). It is moving faster at B.
Explanation:
Given that,
Charge = -5.00μC
Mass of particle
Potential at point A= 200 V
Potential at point B= 800 V
Speed of particle at point A = 5.00 m/s
We need to calculate the speed at point B
Using law of conservation of energy
Put the value into the formula
Hence, (a). The speed at point B is 7.41 m/s.
(b). It is moving faster at B.
Answer:
D. 1/16 It's weight on the surface.
Explanation:
As we know that the gravity due to earth at its surface is given as
now at the distance of 4 radius of earth the gravity is given as
so we can say that
so here gravity becomes 1/16 times of the gravity due to earth on its surface
now we know that weight on the surface of earth is given as
also the weight now at the given height is given by
so here correct answer will be
D. 1/16 It's weight on the surface.
E = F/q
F = 8.4 N
Q = -8.8 uC
E = 8.4 N / - 8.8 x 10^6 C
= -9.5 x 10^-7 N/C
If the result of this kind of equation resulted in negative, the direction of the electric field will be upward
hope this helps
Answer:
The math club needs 25 uniforms for girls and 10 uniforms for boys.
Explanation:
To solve this problem we must follow every step of the statement
We raise each of the incognites:
B = boys
G = girls
The first equation:
B + G = 35
And the second equation; using the expression "there are 5 more girls than twice the number of boys in the club".
G = 2*B + 5
Now we replace in the first equation:
B + (2*B+5) = 35
B + 2*B + 5 = 35
3*B = 30
B = 10
and
G = 35 - 10
G = 25
Therefore, the math club needs 25 uniforms for girls and 10 uniforms for boys