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vampirchik [111]
2 years ago
8

How many coulombs of positive charge are there in 0.1 kg of carbon? Twelve grams of carbon contain Avogadro's number of atoms, w

ith each atom having six protons and six electrons.
Physics
1 answer:
krek1111 [17]2 years ago
6 0

Answer:

481.84\times 10^{4}

Explanation:

We have given the mass of the carbon =0.1 kg

Molar mass of the carbon =12 gram

Number of moles n=\frac{0.1}{0.012}=8.333

We know that 1 mole of carbon contain 6.023\times 10^{23}atoms

So atoms contained by 8.333 moles =8.333\times 6.023\times 10^{23}=50.191\times 10^{23}atoms

In question it is given that each atom contain 6 proton so number of proton 6\times 50.191\times 10^{23}atoms=301.15\times 10^{23}proton

Now we know that each proton contain positive charge of 1.6\times 10^{-19}C

So total charge =1.6\times 10^{-19}\times 301.15\times 10^{23}=481.84\times 10^{4}C

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A 3.1 kg ball is dropped from the top of a 38 m tall building. What is the speed of the ball when it is halfway from the buildin
Archy [21]

Answer:

19.3m/s

Explanation:

Use third equation of motion

v^2-u^2=2gh

where v is the velocity at halfway, u is the initial velocity, g is gravity (9.81m/s^2) and h is the height at which you'd want to find the velocity

insert values to get answer

v^2-0^2=2(9.81m/s^2)(38/2)\\v^2=9.81m/s^2 *38\\v^2=372.78\\v=\sqrt[]{372.78} \\v=19.3m/s

4 0
2 years ago
Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light.
pogonyaev

Complete Question

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light

Answer:

The diameter is  D = 0.59 \  m    

Explanation:

From the question we are told that

      The best resolution is  \theta  =  0.3 \  arcsecond

       The  wavelength is  \lambda  =  700 \  nm =  700 *10^{-9 } \  m

       

Generally the

         1 arcminute  = >  60 arcseconds

=>      x arcminute =>   0.3 arcsecond

So

       x =  \frac{0.3}{60 }

=>    x = 0.005 \  arcminutes

Now

         60 arcminutes  =>  1 degree

          0.005 arcminutes = >  z degrees  

=>       z =  \frac{0.005}{60 }

=>      z =  8.333 *10^{-5}  \ degree

Converting to radian  

           \theta  = z =  8.333 *10^{-5}  * 0.01745 = 1.454 *10^{-6} \  radian

Generally the resolution is mathematically represented as

            \theta  =  \frac{1.22 *  \lambda  }{ D}

=>    D =  \frac{1.22 * \lambda }{\theta }

=>     D =  \frac{1.22 * 700 *10^{-9} }{ 1.454 *10^{-6} }    

=>     D = 0.59 \  m    

4 0
2 years ago
The ____ of a position-time graph represents an object’s velocity.
Marianna [84]

Answer:

The slope of a position-time graph represents an object’s velocity.

Explanation:

In a position-time graph, the values on the x-axis represent the time, while the values on the y-axis represent the position of the object.

Velocity is defined as the ratio between the displacement of an object and the time taken:

v=\frac{\Delta s}{\Delta t}

However, we can see that this definition corresponds to the slope of the curve in a position-time graph. In fact:

\Delta s, the displacement, corresponds to the difference in position, so the difference between the values on the y-axis: \Delta s=y_2 -y_1

\Delta t, the time interval, corresponds to the difference in times, so the difference between the values on the x-axis: \Delta t= t_2 -t_1=x_2 -x_1

So, the velocity is

v=\frac{\Delta s}{\Delta t}=\frac{y_2 -y_1}{x_2 -x_1}

which corresponds to the slope of the curve.

3 0
3 years ago
Read 2 more answers
Does Pepsi have more carbonation than coke
horsena [70]
Coke has more fizz than Pepsi, because Coke has more carbonation in it. Pepsi contains more sugar (2 more tablespoons) than Coke, so it tastes slightly sweeter to many people.
6 0
3 years ago
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When light is directed on a metal surface, the kinetic energies of the photoelectrons a) are random b) vary with the frequency o
jekas [21]

Answer:

b) vary with the frequency of the light

Explanation:

The phone electric effect can be expressed as

K.E=(hv -W•)

Where K.E is the Kinectic energy

W• = work function of the metal

ν =frequency of the radiation

h = Planck's constat

Then, we can see that K.E is proportional linearly to "v" in the equation above.

Therefore, When light is directed on a metal surface, the kinetic energies of the photoelectrons vary with the frequency of the light

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2 years ago
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