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vampirchik [111]
3 years ago
8

How many coulombs of positive charge are there in 0.1 kg of carbon? Twelve grams of carbon contain Avogadro's number of atoms, w

ith each atom having six protons and six electrons.
Physics
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

481.84\times 10^{4}

Explanation:

We have given the mass of the carbon =0.1 kg

Molar mass of the carbon =12 gram

Number of moles n=\frac{0.1}{0.012}=8.333

We know that 1 mole of carbon contain 6.023\times 10^{23}atoms

So atoms contained by 8.333 moles =8.333\times 6.023\times 10^{23}=50.191\times 10^{23}atoms

In question it is given that each atom contain 6 proton so number of proton 6\times 50.191\times 10^{23}atoms=301.15\times 10^{23}proton

Now we know that each proton contain positive charge of 1.6\times 10^{-19}C

So total charge =1.6\times 10^{-19}\times 301.15\times 10^{23}=481.84\times 10^{4}C

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kogti [31]

Answer:

The initial velocity of the snowball was 22.21 m/s

Explanation:

Since the collision is inelastic, only momentum is conserved. And since the snowball and the box move together after the collision, they have the same final velocity.

Let m_1 be the mass of the ball, and v_1 be its initial velocity; let m_2 be the mass of the box, and v_2 be its velocity; let v_f be the final velocity after the collision, then according to the law of conservation of momentum:

m_1v_1+m_2v_2=v_f(m_1+m_2).

From this we solve for v_1, the initial velocity of the snowball:

\boxed{v_1=\frac{v_f(m_1+m_2)-m_2v_2}{m_1}}

now we plug in the numerical values m_1=0.199\:kg, m_2=2.89\:kg, v_2=0.523\:m/s, and v_f=1.92\:m/s to get:

v_1=\frac{1.92*(0.199+2.89)-2.89*0.523}{0.199}

\boxed{v_1=22.21\:m/s}

The initial velocity of the snowball is 22.21 m/s.

<em>P.S: we did not take vectors into account because everything is moving in one direction—towards the west.</em>

4 0
3 years ago
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Answer:

70mi/h

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