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vampirchik [111]
3 years ago
8

How many coulombs of positive charge are there in 0.1 kg of carbon? Twelve grams of carbon contain Avogadro's number of atoms, w

ith each atom having six protons and six electrons.
Physics
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

481.84\times 10^{4}

Explanation:

We have given the mass of the carbon =0.1 kg

Molar mass of the carbon =12 gram

Number of moles n=\frac{0.1}{0.012}=8.333

We know that 1 mole of carbon contain 6.023\times 10^{23}atoms

So atoms contained by 8.333 moles =8.333\times 6.023\times 10^{23}=50.191\times 10^{23}atoms

In question it is given that each atom contain 6 proton so number of proton 6\times 50.191\times 10^{23}atoms=301.15\times 10^{23}proton

Now we know that each proton contain positive charge of 1.6\times 10^{-19}C

So total charge =1.6\times 10^{-19}\times 301.15\times 10^{23}=481.84\times 10^{4}C

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When we press ball inside water it tries to come upwards, why​
bekas [8.4K]

Answer:

hope this helps

Explanation:

an object that's less dense than water floats (eg , ball) because the water it displaces weighs more than the object does. If you've ever tried pushing a beach ball underwater , you've felt this principle in action. As we push the ball down , it pushes back up .

6 0
3 years ago
When a metal rod is heated, its resistance changes both because of a change in resistivity and because of a change in the length
monitta

Answer:

3.34\Omega

Explanation:

The resistance of a metal rod is given by

R=\frac{\rho L}{A}

where

\rho is the resistivity

L is the length of the rod

A is the cross-sectional area

The resistivity changes with the temperature as:

\rho(T)=\rho_0 (1+\alpha (T-T_0))

where in this case:

\rho_0 is the resistivity of silver at T_0=21.0^{\circ}C

\alpha=6.1\cdot 10^{-3} ^{\circ}C^{-1} is the temperature coefficient for silver

T=180.0^{\circ}C is the current temperature

Substituting,

\rho(180^{\circ}C)=\rho_0 (1+6.1\cdot 10^{-3}(180-21))=1.970\rho_0

The length of the rod changes as

L(T)=L_0 (1+\alpha_L(T-T_0))

where:

L_0 is the initial length at 21.0^{\circ}C

\alpha_L = 18\cdot 10^{-6} ^{\circ}C^{-1} is the coefficient of linear expansion

Substituting,

L(180^{\circ}C)=L_0(1+18\cdot 10^{-6}(180-21))=1.00286L_0

The cross-sectional area of the rod changes as

A(T)=A_0(1+2\alpha_L(T-T_0))

So, substituting,

A(180^{\circ}C)=A_0(1+2\cdot 18\cdot 10^{-6}(180-21))=1.00572A_0

Therefore, if the initial resistance at 21.0°C is

R_0 = \frac{\rho_0 L_0}{A_0}=1.70\Omega

Then the resistance at 180.0°C is:

R(180^{\circ}C)=\frac{\rho(180)L(180)}{A(180)}=\frac{(1.970\rho_0)(1.00285L_0)}{1.00572A_0}=1.9644\frac{\rho_0 L_0}{A_0}=1.9644 R_0=\\=(1.9644)(1.70\Omega)=3.34\Omega

7 0
3 years ago
Hello, I want to ask. . anyone knows the answer.
sasho [114]

Answer:

C?

Explanation:

Please give brainliest.

5 0
3 years ago
Canada’s northern territories experience "midnight sun," meaning what?.
Leona [35]

Answer:

Explanation:   The term "midnight sun" refers to the consecutive 24-hour periods of sunlight experienced in the north of the Arctic Circle and south of the Antarctic Circle. Other phenomena are sometimes referred to as "midnight sun", but they are caused by time zones and the observance of daylight saving time.

6 0
3 years ago
Please help!! This is the last question and i’m unsure! I will mark brainliest! Please try to provide a explanation you don’t ha
Flauer [41]

Answer:

True

Explanation:

As of Newton's law, yes. Because when I land my feet on the ground, I apply a force. As per Newton's third law, the ground must apply the same force on me.

If its correct, may I hv brainliest?

7 0
3 years ago
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